The equation is P= 2w + 2(w+4.1)
The width is 8.2cm
Answer:
to find the distance between two points, in order to find the length of the triangle we need first to find the instance between the two points
distance between (2,9) and (2,4) .....a =5
distance between (2,4) and (6,4) .....b = 4
when we find the length of the side of the triangle , then we can apply the Pythagorean theorem to find hyp. c
a²+b²=c²
10) V=πr² *h= π*10²*12≈3770
11) V=A(base)*h= (3√3/2)*(9²)*10=2104
A(base)=(P*a)/2=(6*9*3√3)/2=9*9*3√3/2
12)V=πr² *h=π*18² *6≈6107
13)V=4*3*12=144
14) h(triangle)=√(5²-3²)=√16=4
A(base)=(3*4)/2=6
V=A(base)* height (prism)=6*2=12
15) V=A(base)*h= (3√3/2)*(6²)*11= 1029
16)V=A(base)*h=2(1+√2)5²*22≈2656
Answer: The answer is (B).
Step-by-step explanation: We are given four options and we are to select which matrix can be multiplied to the left of a vector matrix to get a new vector matrix. The order of a vector matrix is either n × 1 or 1 × n.
For (A): The order of the matrix is 2 × 1. If we multiply this matrix by a vector matrix of order 1 × 2, then the resulting matrix will be of order 2 × 2, which is not a vector matrix.
For (B): The order of the matrix is 3 × 2. If we multiply this matrix by a vector matrix of order 2 × 1, then the resulting matrix will be of order 3 × 1, which is a new vector matrix.
For (C): The order of the matrix is 2 × 2. If we multiply this matrix by a vector matrix of order 2 × 1, then the resulting matrix will be of order 2 × 1, which is a vector matrix of order same as before.
For (D): The order of the matrix is 1 × 2. If we multiply this matrix by a vector matrix of order 2 × 1, then the resulting matrix will be of order 1 × 1, which is a not vector matrix.
Thus, the correct option is (B).
Step-by-step explanation:
Given
w(x) = - 3x - 4
Now
w(7) = - 3 * 7 - 4
= - 21 - 4
= - 25
Hope it will help :)❤