The line has equation
where 
is any real number. 
is the line containing all scalar multiples of the vector (-1, 4, -3); we add (4, -4, 8) to shift the line so that it passes through this point while remaining parallel to the the line.
To get the symmetric form, we have
Solving for in each equation gives the symmetric form,
The line has intercepts in the coordinate planes wherever either the 
, 
, or 
coordinate is 0.
-plane:
-plane:
-plane:
Answer:
radius=diameter÷2=36÷2=13
Answer:
C. 120
Step-by-step explanation:
Hope it helps!
Answer:
Step-by-step explanation:
You can't ever let this go negative. At least not at the grade you are in.
It can be 0.
So the domain must start at x = 7
sqrt(5*7 - 35) = sqrt(0) = 0
x can have any value (including 7) between 7 and infinity. If you choose a number less than 7 (like 6) the square root will go negative and that's not to be done.
So the interval is
7 ≤ x < ∞
120 + 90 = 210 points
350 - 210 = 140 OR
351 - 210 = 141 (if it must be more than 350, you need <em>at least </em>351 points total, or 141 more points, to get a grade B)
