All categories

3 years ago

What is the value of the fourth term in a geometric sequence for which a = 110 and r=0.5?

Mathematics

1 answer:

zavuch27 [327]3 years ago

3 0

110(0.5^3)=13.75
The answer is 13.75

You might be interested in

Carleen has 104 pieces of candy leftover from Halloween. She would like to distribute them evenly to the 8 kids on her block. Wr

algol13

Answer:

8x = 104

x = 13

Step-by-step explanation:

Since we are trying to distribute it evenly, we divide 104 by 8 to get 13 pieces of candy per child.

The equation is saying 8 kids times x amount of candy per kid is equal to a total amount of 104 pieces of candy.

4 0

3 years ago

Read 2 more answers

Convert 6 20 into a decimal

lakkis [162]

Answer:

6.20

wait what do u mean

6 0

3 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers

2n-n-4+7n in simplest form

MrMuchimi

2n-n-4+7n in simplest form is found by combining like terms:

(2-1+7)n - 4 = 8n-4, or 4(2n-1)

6 0

3 years ago

A man buys a book for Rs 400 and sells it for Rs 420 his profit is

motikmotik

Answer:

Step-by-step explanation:

420-400=20

6 0

3 years ago

Read 2 more answers