2 years ago

Solve the following equation for H. Be sure to take into account whether a letter is

Mathematics

1 answer:

MrMuchimi2 years ago

7 0

Answer:

$H=n-8$

Step-by-step explanation:

$8+H=n$

$\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides}$

$8+H-8=n-8$

$Simplify$

$H=n-8$

You might be interested in

Write the equation of the line with a slope of 3/4 and a y'-intercept of -7 in Slope-Intercept and Poin Slope Form.

Shtirlitz [24]

Slope intercept form: y = 3/4 x - 7
Point slope form: y + 7 = 3/4 (x+0)

4 0

1 year ago

What equation is equivalent to 1/3 (9x+12) + 4x + 6

Irina-Kira [14]

The answer is b, 7x+10

3 0

2 years ago

Read 2 more answers

Solve y′′=sin(x) if y(0)=0 and y′(0)=5.<br><br> y(x)=?

Ksenya-84 [330]

Answer:

$y(x)=6x-sin(x)$

Step-by-step explanation:

Rewrite the differential equation as:

$\frac{d^{2} y }{dx^{2} } =sin(x)$

Integrate both sides with respect to x:

$\int\ \frac{d^{2} y }{dx^{2} } dx = \int\ sin(x) dx$

$\frac{dy}{dx} =-cos(x)+C_1$

Integrate one more time both sides with respect to x:

$\int\ \frac{dy}{dx} = \int\ -cos(x)+C_1 dx$

$y(x)=-sin(x)+C_1x+C_2$

Now that we find the solution, let's find its derivate:

$y'(x)=C_1-cos(x)$

Evaluating the initial conditions:

$y(0)=C_1(0)+C_2-sin(0)=0\\C_2=0$

$y'(0)=C_1-cos(0)=5\\C_1=5+1=6$

Replacing the value of the constants that we found in the differential equation solution:

$y(x)=6x-sin(x)$

6 0

2 years ago

Y^2(3y−4) + 7(3y−4) Factor the polynomial as the product of two binomials.

Usimov [2.4K]

First, factor the (3y-4) and group the remaining terms
y²(3y-4) +7 (3y-4)
(y²+7)(3y-4)
I hope this helps (:

7 0

2 years ago

Read 2 more answers

PLease help

Mariulka [41]

Answer:

the brain performs at its optimum level

Step-by-step explanation:

answer on edg 2020

5 0

2 years ago

Read 2 more answers