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nikdorinn [45]
1 year ago
14

Please help with these problems having trouble!!

Mathematics
1 answer:
77julia77 [94]1 year ago
4 0

The function f(x) is vertically compressed to form g(x) while the function f(x) is vertically compressed and then reflected across the x-axis to form h(x)

<h3>How to compare both functions?</h3>

The functions are given as

f(x) =x^2

g(x) =3x^2

h(x) = -3x^2

Substitute f(x) =x^2 in g(x) =3x^2 and h(x) = -3x^2

g(x) =3f(x)

h(x) = -3f(x)

This means that the function f(x) is vertically compressed to form g(x)

Also, the function f(x) is vertically compressed and then reflected across the x-axis to form h(x)

See attachment for the functions g(x) and h(x)

Also, functions f(x) and g(x) have the same domain and range

While functions f(x) and h(x) have the same domain but different range

The complete table is:

x      -2    -1    0   1    2

g(x)  12    3    0    3   12

h(x)  -12    -3    0    -3   -12

Read more about function transformation at:

brainly.com/question/13810353

#SPJ1

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For each question (a–e) below, choose one of the answers (i–viii); explain your choice.
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Step-by-step explanation:

given that a deck of cards is shuffled.

we know in a deck there are 52 cards, 13 cards of each variety spade, clubs hearts and dice.  Red are 26 and black are 26.  kings, will be 4.

(a) the top card is the king of spades and the bottom card is the queen of spades?

(iii) 1/52 × 1/52

Top has 1/52 and bottom has 1/52 and these are independent.

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(viii) None of the above

Because it is impossible.

(c) the top card is the king of spades or the bottom card is the king of spades?

(iv) 1/52 + 1/52

This is the sum of probabilities because there is no common event for these two.

(d) the top card is the king of spades or the bottom card is the queen of spades?

(ii) 1/52 + 1/51 (once king of spades is there, then probability is 1/51 for bottom card)

(e) of the top and bottom cards, one is the king of spades and the other is the queen of spades?

(vii) 2/52 × 1/51

Because this is twice of probability d.

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The term "freshman 15" refers to the claim that college students typically gain 15lbs during freshman year at college. Assume th
Viefleur [7K]

The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%

<h3>What is Probability ?</h3>

Probability is defined as the likeliness of an event to happen.

Let X be a random variable that shows the term "freshman 15" that claims that students typically gain 15lb during their freshman year at college.

It is given that

X follows is a normal distribution with a mean of 2.1 lb (μ) and a standard deviation (σ)  of 10.8 lb.

Population Mean (μ) = 2.1

Population Standard Deviation (σ) = 10.8

We need to compute Pr(X≥15). The corresponding z-value needed to be computed is:

\rm Z_{lower} = \dfrac{ X_1 -\mu }{\sigma}\\\\Z_{lower} = \dfrac{ 15-2.1 }{10.8}\\\\\\Z_{lower} = 1.19

Then the probability is given as

\rm Pr(X \geq 16 ) = Pr (\dfrac{X -21}{10.8} \geq \dfrac{15-21}{10.8})\\\\= Pr (Z \geq \dfrac{15-2.1}{10.8}\\\\= Pr (Z\geq 1.19)\\\\ = 0.1162

Pr(X≥15)=0.1162. (11.6%)

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To know more about Probability

brainly.com/question/11234923

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