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juin [17]
3 years ago
5

1.) What is the independent variable?

Mathematics
2 answers:
Advocard [28]3 years ago
8 0

Answer:

1. # of minutes

2. # of words

Step-by-step explanation:

The words depend on how long you read

Nataly [62]3 years ago
6 0

Answer:

The independent variable is the number of minutes spent typing. The dependent variable is the number of words typed

Step-by-step explanation:

You might be interested in
Identify the solutions to (2x - 4)(x + 10) = 0
Karolina [17]
Answer:
-10,2

Solve by factoring set each equation equal to 0.
2x-4=0
X+10=0
Simplify
8 0
3 years ago
Read 2 more answers
If P = 4x^4 - 3x^3 + x² - 5x + 11 and Q = -3x^4 + 6x^3 - 8x² + 4x - 3, what is P - 2Q?
vazorg [7]

Answer:

10x^4-15x^3+17x^2-13x+17

Step-by-step explanation:

P-2Q

Replace P and Q with the given values,

4x^4-3x^3+x^2-5x+11-(2(-3x^4+6x^3-8x^2+4x-3)

4x^4-3x^3+x^2-5x+11-(-6x^4+12x^3-16x^2+8x-6)

4x^4-3x^3+x^2-5x+11+6x^4-12x^3+16x^2-8x+6

10x^4-15x^3+17x^2-13x+17

7 0
2 years ago
Gordon types 1,800 words in 25 minutes how many words per hour?
ANEK [815]
45000 is the answer because 1800 x 25 = 45000

8 0
3 years ago
Read 2 more answers
What is the quotient of -5.2÷3.9
irina [24]
1.333333333... quotient
6 0
3 years ago
A business executive bought 40 stamps for
alekssr [168]

Answer:

32 33-cent stamps, 8 23-cent stamps

Step-by-step explanation:

In order to solve this question, we need to set up a system of equations. Also known as solving for two variables (the number of each stamp).

Let's set x to be the number of 33-cent stamps. Similarly, let's set y to be the number of 23-cent stamps.

To make our first equation, let's think about the number of stamps total we have. We can say:

x + y =40

<em>(AKA - The number of 33-cent stamps, plus the number of 23-cent stamps, equals 40 stamps.)</em>

Now, let's make an equation for the cost of these stamps.

0.33x + 0.23y = 12.40

<em>(AKA - The cost of the stamps in total, should equal $12.40).</em>

So now, we have our two equations:

x + y =40\\0.33x+0.23y=12.40

If you have a TI-84 graphing calculator, you can go to apps -> polysmlt2 -> simultaneous eqn solver, and then input these equations into the menu. This will solve the problem for you.

If you need to do this manually, let's use substitution. Condense our first equation to make it more substitutable.

x+y=40\\x=40-y

Now, let's put this into our second equation.

0.33x+0.23y=12.40\\0.33(40-y)+0.23y=12.40

Distribute, and solve for y.

13.2-0.33y +0.23y =12.40\\13.2-0.1y=12.40\\-0.1y=-0.8\\y=8

Now, we plug this into one of our equations.

x+y=40\\x+8=40\\x=32

In the end, we have thirty-two 33-cent stamps, and eight 23-cent stamps.

3 0
1 year ago
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