Answer:
A pound of a JELLY BEANS cost $2.5
A pound of TRAIL MIX cost $1.5
Step-by-step explanation:
From the question, we can draw out two equations and solve them simultaneously.
We should make some mild assumptions to make it easier:
Let Jelly beans be j
Let Trail mix be t
Therefore, we can extract these equations.
5j + 3t =$ 17 ...........i
2j + 12t = $ 23...…..ii
Let's Multiply equation (I) by 4 so that we can easily eliminate.
20j + 12t = $ 68..... iii
Let equation (iii) minus equation (ii)
18j + 0t = $45
18j = $45
j = $45/18
j = $2.5
A pound of a JELLY BEANS cost $2.5
Let's substitute j= $2.5 in EQUATION (I) so as to solve for TRAIL MIX.
5j + 3t =$ 17
5(2.5) + 3t = 17
12.5 + 3t = 17
3t = 17 - 12.5
3t = 4.5
t = $1.5
A pound of TRAIL MIX cost $1.5
a) The linear function that models the population in t years after 2004 is: P(t) = -200t + 29600.
b) Using the function, the estimate for the population in 2020 is of 26,400.
<h3>What is a linear function?</h3>
A linear function is modeled by:
y = mx + b
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.
The initial population in 2004, of 29600, is the y-intercept. In 12 years, the population decayed 2400, hence the slope is:
m = -2400/12 = -200.
Hence the equation is:
P(t) = -200t + 29600.
2020 is 16 years after 2004, hence the estimate is:
P(16) = -200(16) + 29600 = 26,400.
More can be learned about linear functions at brainly.com/question/24808124
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The area would be approximately 153.94.
The area of a circle is pie multiplied by r^2.
So you have the radius, which is r. Plug in r. Technically you have two numbers because pie equals approximately 3.14.
A=3.14(7)^2
Answer:
Specific Learning Outcomes:
Solve problems that involve finding powers of a number
Description of mathematics:
In this problem students work with powers of numbers and, as a consequence, come to understand what is happening to the numbers.
Students also see how an apparently enormous and difficult calculation can be broken down into manageable parts. The students should come to realise that there are only a limited number of unit digits obtained when 7 is raised to a power. Further, these specific digits 'cycle round' as the power of 7 increases. This cycle is 7, 9, 3, 1, 7, 9, …
The same is true of the digit in the tens place.
