I’m pretty sure it’s 2 but i’m not 100 percent on that
Answer:
not
Step-by-step explanation:
![\left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] *\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right]=](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D%20%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%5C%5C3%267%5Cend%7Barray%7D%5Cright%5D%3D)
First is A and Second is B
Let's find A*B
![\left[\begin{array}{ccc}-2(-2)+4*3&-2*1+4*7\\1(-2)+3*3&1*1+3*7\end{array}\right] =\left[\begin{array}{ccc}16&26\\7&22\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%28-2%29%2B4%2A3%26-2%2A1%2B4%2A7%5C%5C1%28-2%29%2B3%2A3%261%2A1%2B3%2A7%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%2626%5C%5C7%2622%5Cend%7Barray%7D%5Cright%5D)
b)
![\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right] \left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] =](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%5C%5C3%267%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D%20%3D)
Now let's find B*A
![\left[\begin{array}{ccc}-2(-2)+1*1&-2*4+1*3\\3(-2)+7*1&3*4+7*3\end{array}\right] =\left[\begin{array}{ccc}5&-5\\1&23\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%28-2%29%2B1%2A1%26-2%2A4%2B1%2A3%5C%5C3%28-2%29%2B7%2A1%263%2A4%2B7%2A3%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-5%5C%5C1%2623%5Cend%7Barray%7D%5Cright%5D)
c) They are not
To solve this problem you must apply the proccedure shown below:
1. You have the following information given in the problem above:
- The<span> room has square dimensions and it has been built with two pieces of sheetrock, a smaller one and a larger one.
2. Therefore, let's call
x: the smaller one.
y: the larger one.
3. Then, you have that the lenght of the wall is the sum of the smaller one and the larger one:
x+y
4. So, the area of the room is:
(x+y)(x+y)
(x+y)</span>²
Therefore, the answer is: (x+y)²
Answer:
Option B,C and E are solution to given inequality 
Step-by-step explanation:
We need to check which ordered pairs from given options satisfy the inequality 
Ordered pairs are solutions to inequality if they satisfy the inequality
Checking each options by pitting values of x and y in given inequality
A ) (1, -5)

So, this ordered pair is not the solution of inequality as it doesn't satisfy the inequality.
B) (-3, - 2)

So, this ordered pair is solution of inequality as it satisfies the inequality.
C) (0, -9)

So, this ordered pair is solution of inequality as it satisfies the inequality.
D) (2, -1)

So, this ordered pair is not the solution of inequality as it doesn't satisfy the inequality.
E) (5, 4)

So, this ordered pair is solution of inequality as it satisfies the inequality.
So, Option B,C and E are solution to given inequality 
Step-by-step explanation:
the sum of all angles in a triangle is always (ALWAYS !) 180°.
180 = 31 + 35 + x = 66 + x
x = 180 - 66 = 114°