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lina2011 [118]
3 years ago
10

Help me with math Pleaseeeeeeeeeeeee

Mathematics
1 answer:
solong [7]3 years ago
6 0

Answer:

Your answer is C. Hope this helped. :)

Step-by-step explanation:

a^2 + b^2 = c^2

32^2 + 18^2 = c^2

1024 + 324 = c^2

√(1348) = 36.7

= 37

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Arrange0.2,¼,30%,10%in ascending and descending order​
BARSIC [14]

Answer:

Ascending- 10%, 0.2, 1/4, 30%

Descending- 30%, 1/4, 0.2, 10%

Step-by-step explanation:

0.2 = 2/10 = 4/20

1/4 = 5/20

30% = 30/100 = 6/20

10% = 10/100 = 2/20

Ascending

-2/20, 4/20, 5/20, 6/20

- 10%, 0.2, 1/4, 30%

Descending

- 6/20, 5/20, 4/20, 2/20

- 30%, 1/4, 0.2, 10%

7 0
3 years ago
An angle in standard position measures radians, and P(0, 1) is on the terminal side of the angle. What is the value of the cosin
lana [24]
Answer: 0

Explanation:

1) Cosine trigonometric ratio definition:

cos (α) = adjacent-leg / hypotenuse

2) P (0,1) ⇒ 

- adyacent-leg = x-coordinate = 0
- opposite-leg = y-coordinate = 1
- hypotenuse = √[x² + y² ] = 1

3) Therefore, cos(α) = 0 / 1 = 0

8 0
4 years ago
Read 2 more answers
HELPPPPP PLS!!!!!!!!!!
nika2105 [10]

Answer:

1 no is correct

Step-by-step explanation:

because 2 cube is 8

So , 2 × 2 =4 ×2 = 8

5 0
3 years ago
This is the question...plz hurry..thx
svetlana [45]

Answer:

20x-21y+14

Step-by-step explanation:

1/5(100x-105y+70)

20x-21y+14

6 0
3 years ago
In 2015, Oklahoma experienced 907 perceptible earthquakes (far surpassing California), for an average of about 2.5 perceptible e
Rufina [12.5K]

Answer:

The probability P of a day with no perceptible earthquakes is 0.0821.

Step-by-step explanation:

We will consider that earthquakes occurring in a day is a <u>Poisson process</u>. The following Poisson probability distribution formula will be used in this question.

<u>p(x,λ) = [e^-λ (λ)ˣ]/x!</u>

where x = number of outcomes occurring

           λ = mean number of occurrences

(a) So, in this question we have λ = 2.5 and we need to find the probability that x=0 (no perceptible earthquakes in a day). So,

P(X=0) = p(0,2.5) = [(e^-2.5)(2.5)⁰]/0!

                            = ((0.0821)*1)/1

P(X=0) = 0.0821

The probability P of a day with no perceptible earthquakes is 0.0821.

6 0
4 years ago
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