What value of X would make U tangent to circle P at point Q
2 answers:
the correct question is
<span>What value of x would make RQ tangent to Circle P at point Q?
the picture in the attached figure
we know that
If RQ is a tangent to circle P at point Q
then
</span>RQ is perpendicular to the radius PQ at the point of tangency Q.
This means that ΔPRQ would be a right triangle.
Applying Pythagorean theorem
RP²=PQ²+RQ²
(x+9)²=9²+12²
(x+9)²=225
(+/-)(x+9)=√225
(+/-)(x+9)=15
+(x+9)=15-----> x=15-9-----> x=6
-(x+9)=15-----> -x-9=15-----> x=-9-15-----> x=-24
the solution is
x=6
the answer is
x=6 units
<span>What value of x would make RQ tangent to Circle P at point Q?
the picture in the attached figure
we know that
If RQ is a tangent to circle P at point Q
then
</span>RQ is perpendicular to the radius PQ at the point of tangency Q.
This means that ΔPRQ would be a right triangle.
Applying Pythagorean theorem
RP²=PQ²+RQ²
(x+9)²=9²+12²
(x+9)²=225
(+/-)(x+9)=√225
(+/-)(x+9)=15
+(x+9)=15-----> x=15-9-----> x=6
-(x+9)=15-----> -x-9=15-----> x=-9-15-----> x=-24
the solution is
x=6
the answer is
x=6 units
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Answer:
see below
Step-by-step explanation:
First of all, you want to find the data set the matches the extreme values of 5 and 35. That eliminates the 2nd and 4th choices.
Then you want to find the data set that has a median of 15. The first data set has a middle value (median) of 20, so that choice is eliminated.
The data set of the 3rd choice matches the box plot extremes, median, and quartile values.
