What value of X would make U tangent to circle P at point Q
2 answers:
the correct question is
<span>What value of x would make RQ tangent to Circle P at point Q?
the picture in the attached figure
we know that
If RQ is a tangent to circle P at point Q
then
</span>RQ is perpendicular to the radius PQ at the point of tangency Q.
This means that ΔPRQ would be a right triangle.
Applying Pythagorean theorem
RP²=PQ²+RQ²
(x+9)²=9²+12²
(x+9)²=225
(+/-)(x+9)=√225
(+/-)(x+9)=15
+(x+9)=15-----> x=15-9-----> x=6
-(x+9)=15-----> -x-9=15-----> x=-9-15-----> x=-24
the solution is
x=6
the answer is
x=6 units
<span>What value of x would make RQ tangent to Circle P at point Q?
the picture in the attached figure
we know that
If RQ is a tangent to circle P at point Q
then
</span>RQ is perpendicular to the radius PQ at the point of tangency Q.
This means that ΔPRQ would be a right triangle.
Applying Pythagorean theorem
RP²=PQ²+RQ²
(x+9)²=9²+12²
(x+9)²=225
(+/-)(x+9)=√225
(+/-)(x+9)=15
+(x+9)=15-----> x=15-9-----> x=6
-(x+9)=15-----> -x-9=15-----> x=-9-15-----> x=-24
the solution is
x=6
the answer is
x=6 units
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Answer:
so, the figure here is a cylinder with a semi sphere on the top, we know the height of whole structure, and the radius of the semi sphere, which is the same as the radius of the cylinder (you can see it because the radius of the semisphere is constant, and you can thin on it as half a sphere over a cylinder).
First, the cylinder will be the structure without the semi sphere, so his height will be te total height minus the radius of the semi sphere, which is 0.9μm.
so now we know the height and the radius of the cylinder, the surface or the sides of it is 2*3.14*r*h = 2*3.14*0.9μm*0.1μm = 0.5662.
Answer:
The probability that the card selected bears a number less than 34 is 0.3333.
Step-by-step explanation:
Let random variable <em>X</em> be defined as the number on the selected card.
There are <em>N</em> = 15 total cards.
The number on the cards are as follows:
S = {25, 26, 27,..., 38, 39}
The probability of an event, <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.
In this case we need to compute the probability that the card selected bears a number less than 34.
The favorable outcomes are:
<em>s</em> = {25, 36, 37, 38, 39}
<em>n</em> (X < 34) = 5
Compute the probability that the card selected bears a number less than 34 as follows:
Thus, the probability that the card selected bears a number less than 34 is 0.3333.