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Eva8 [605]
3 years ago
10

What is the true solution to 2 In eln 5x – 2 In 15?

Mathematics
1 answer:
babunello [35]3 years ago
6 0

Answer:

x = 49.84

Step-by-step explanation:

We are given an equation of unknown x and we have to solve the equation for x.

2\ln(e\ln5x)-2\ln15 =0

⇒ ln(e\ln5x) = \ln15

⇒ \ln e + \ln \ln 5x = \ln 15 {Since we know that  ln AB =ln A + ln B}

⇒ \ln \ln 5x = \ln 15 -\ln e

⇒ \ln \ln 5x=\ln \frac{15}{e} {Since we know that ln A/B = ln A - ln B}

⇒ \ln 5x = \frac{15}{e}

⇒ 5x = e^{\frac{15}{e} }

⇒ x = \frac{1}{5} e^{\frac{15}{e} }{Converting logarithm to exponent form}

⇒ x = 49.84 (Approximate) (Answer)

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Answer:

41.29 cm²

Step-by-step explanation:

From the question,

Area of the shaded portion = Area of the circle - area of the square.

A' = πr²-L²...… Equation 1

Where A' = Area of the shade portion, r = radius of the circle, L = length of the square, π = pie

Given: r = 4 cm, L = 3 cm

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2 years ago
The probability distribution of the amount of memory X (GB) in a purchased flash drive is given below. x 1 2 4 8 16 p(x) .05 .10
Rama09 [41]

Answer:

a) E(X) = 6.45

b) E(X^{2} )= 57.25

c) V(X) = 15.648

d) E(3X + 2) = 21.35

e) E(3X^{2} +2) = 173.75

f) V(3X+2) = 140.832

g) E(X+1) = 7.45

h) V(X+1) = 15.648

Step-by-step explanation:

a) E(X) = \sum xP(x)

E(X) = (1*0.05) + (2*0.10) + (4*0.35) + (8*0.40) + (16*0.10)\\E(X) = 6.45

b)

E(X^{2} ) = (1^{2} *0.05) + (2^{2} *0.10) + (4^{2} *0.35) + (8^{2} *0.40) + (16^{2} *0.10)\\  E(X^{2} )= 57.25

c)

V(X) = E(X^{2} ) - (E(X))^{2} \\V(X) = 57.25 - 6.45^{2} \\V(X) = 15.648

d)

E(3X+2) = 3E(X) + 2\\E(3X+2) = (3*6.45) + 2 \\E(3X+2) = 21.35

e)

E(3X^{2} +2) = 3E(X^{2} ) + 2\\E(3X^{2} +2) = (3*57.25) + 2 \\E(3X^{2} +2) = 173.75

f)

V(3X+2) = 3^{2} V(X)\\V(3X+2) = 9*15.648\\V(3X+2) = 140.832

g)

E(X+1) = E(X) + 1\\E(X+1) = 6.45 + 1\\E(X+1) =7.45

h)

V(X+1) = 1^{2} V(X)\\V(X+1) = 15.648

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Answer:

25-10=15

Step-by-step explanation:

8 0
2 years ago
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