1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexira [117]
3 years ago
5

On a shopping trip, Peter spent 1/3 of his money for a jacket and another $5 for a hat. If peter still had 1/2 of his money left

, how much money did he have originally ??
Mathematics
2 answers:
snow_lady [41]3 years ago
6 0
Let m be the amount of money he had

m - (1/3)m - 5 = (1/2)m
(2/3)m - 5 = (1/2)m
Subtract both sides by (1/2)m
(2/3 - 1/2)m - 5 = 0
(1/6)m - 5 = 0
Add both sides by 5
(1/6)m = 5
Multiply both sides by 6
m = 30

Peter started with 30 dollars.

Have an awesome day! :)
natta225 [31]3 years ago
3 0
He should have started with $30.
You might be interested in
una camisa me costo $10.500, con lo que gaste el 25% de mi dinero ¿cuanto dinero tenia? debe ir desarrollo
evablogger [386]

Answer:

25%------10500

100%------x = 100 * 10500 /25 = 42000

Rta: Tenías 42000

8 0
2 years ago
A company manufactures running shoes and basketball shoes. The total revenue (in thousands of dollars) from x1 units of running
Alborosie

Answer:

x_1 =2 , x_2=7

Step-by-step explanation:

Consider the revenue function given by R(x_1,x_2) = -5x_1^2-8x_2^2 -2x_1x_2+34x_1+116x_2. We want to find the values of each of the variables such that the gradient( i.e the first partial derivatives of the function) is 0. Then, we have the following (the explicit calculations of both derivatives are omitted).

\frac{dR}{dx_1} = -10x_1-2x_2+34 =0

\frac{dR}{dx_2} = -16x_2-2x_1+116 =0

From the first equation, we get, x_2 = \frac{-10x_1+34}{2}.If we replace that in the second equation, we get

-16\frac{-10x_1+34}{2} -2x_1+116=0= 80x_1-2x_1+116-272= 78x_1-156

From where we get that x_1 = \frac{156}{78}=2. If we replace that in the first equation, we get

x_2 = \frac{-10\cdot 2 +34}{2}=\frac{14}{2} = 7

So, the critical point is (x_1,x_2) = (2,7). We must check that it is a maximum. To do so, we will use the Hessian criteria. To do so, we must calculate the second derivatives and the crossed derivatives  and check if the criteria is fulfilled in order for it to be a maximum. We get that

\frac{d^2R}{dx_1dx_2}= -2 = \frac{d^2R}{dx_2dx_1}

\frac{d^2R}{dx_{1}^2}=-10, \frac{d^2R}{dx_{2}^2}=-16

We have the following matrix,  

\left[\begin{matrix} -10 & -2 \\ -2 & -16\end{matrix}\right].

Recall that the Hessian criteria says that, for the point to be a maximum, the determinant of the whole matrix should be positive and the element of the matrix that is in the upper left corner should be negative. Note that the determinant of the matrix is (-10)\cdot (-16) - (-2)(-2) = 156>0 and that -10<0. Hence, the criteria is fulfilled and the critical point is a maximum

8 0
3 years ago
Read 2 more answers
Gabriel ran for 1 mile. Then he started jogging. He jogged for 250 feet. How many total feet did he run and jog?
Marizza181 [45]
1 mile is 5280 feet so when adding both 5,280 and 250 feet you get 5,530.
8 0
3 years ago
The part of a cylindrical soup can that is covered by the label is 8.5 cm tall and has a diameter of 6.5 cm. What is the area of
julia-pushkina [17]

Answer:

180.4~cm^2

Step-by-step explanation:

<u>Surface Area</u>

The surface area of a cylinder of height h and radius r is given by:

A=2\pi rh

It only covers the lateral side of the cylinder. If both the top and the bottom sides are to be included, then:

A=2\pi rh+2\pi r^2

The label will cover only the lateral side of the soup can that has a height of h=8.5 cm and a diameter of 6.5 cm. We need to calculate the radius which is half of the diameter r=6.5 cm / 2 = 3.25 cm.

Now we calculate the side area of the can:

A=2\pi (3.25)(8.5)

A=173.6~cm^2

We need to add the 0.8 cm overlap to the total area already calculated. This overlap has 0.8 cm of width and 8.5 cm of height, so this overlap area is:

A_o= 0.8*8.5=6.8~cm^2

The total area of the label is:

A=173.6~cm^2+6.8~cm^2=180.4~cm^2

The area of the label is \mathbf{180.4~cm^2}

5 0
2 years ago
Yo fr33 points *BLUSHES*
Savatey [412]

Answer:

Pls give question:0

Step-by-step explanation:

4 0
3 years ago
Other questions:
  • How many times can 5 go into 7
    13·2 answers
  • PLEASE HELP ASAP!!!!
    13·1 answer
  • Solve the inequality 9h+2&lt; -79
    5·1 answer
  • 3=4×3/4 what is true about this equation
    11·1 answer
  • Please solve this worksheet. (Factoring trinomials)
    7·1 answer
  • I need help with this question!! please help me
    11·1 answer
  • Can someone explain to me Linear Equations being equivalent?
    11·1 answer
  • A teacher performing a demonstration finds that a piece of cork displaces 23.5 mL of water. The
    5·1 answer
  • Approximately how many square inches of space are blank?
    10·1 answer
  • I’ll mark brainliest
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!