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Ray Of Light [21]
3 years ago
10

On a number line, what is the unit distance between –11 and 3?

Mathematics
2 answers:
Gala2k [10]3 years ago
8 0

Answer:

14

Step-by-step explanation:

if you take 14 - 11 it equals 3 so that is a for sure hard 14

kumpel [21]3 years ago
3 0
The answer is 14

explanation answer: 14
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Alona has some wood cutouts of two different shapes - square and triangle. Each square cutout is 6 mm thick and each triangular
kobusy [5.1K]

Answer:

18

Step-by-step explanation:

Volume is a product of cross-sectional area and height and relresented as V=Ah where V is volume, A is cross-sectional area and h is height.

For the square, since each has a thickness of 6mm then for 24 of them the height will be 24*6=144 mm

Since the volume and cross sectional area of the triangle should be the same, then the height should also be the same.

Since for the triangle each has a thickness of 8mm then the number requred to achieve a height of 144 mm will be 144/8=18 stacks

7 0
4 years ago
Sally has made a scale drawing of the airplane, in which the wingpsan is 10 inches and the tailspan is 3 inches. What is the act
Alina [70]
My first impulse is to say you don't provide enough info with which to solve this problem.  We need to know how many inches in the model correspond to 1 foot in the actual plane (that is, the scale factor).  What is the scale factor here?


4 0
3 years ago
Can some one help me with this
Elza [17]
The first one
is (2,4)

5. is infinitely many solutions

because yu have tovhange the terms plces
4 0
4 years ago
If the diameter of the circle is above 20mm what is the area
mart [117]

Answer:

The area of the circle is 314mm²

Step-by-step explanation:

To solve this problem we have to use the formula for calculating the area of a circle

a = area

π = 3.14

r = radius

d = diameter

r = d/2

r = 20mm / 2

r = 10mm

a = π * r²

we replace the known values

a = 3.14 * (10mm)²

a = 3.14 * 100mm²

a = 314mm²

The area of the circle is 314mm²

3 0
4 years ago
Read 2 more answers
Use Euler's method with step size 0.1 to estimate y(2.5), where y(x) is the solution of the initial-value problem y' = 3y + 2xy,
sweet-ann [11.9K]

Answer:

1.5939 (Correct upto four desimal places)

Step-by-step explanation:

To obtain the large value at x_n=2.5 with small step length h=0.1 and x_0=2,y_0=1,x_n=2.5 , where x_n=x_0+nh we have to use c-programme.  The c-programme for Eular method is given below,

#includestdio.h>

float fun(floatx, floaty)

{

float f;

f=3\times y+2\times x\timesy;

return f;

}

main()

{

float a,b,x,y,h,t,k;

printf("\nEnter x_0,y_0,h,xn:");

scanf("%f%f%f%f",&a,&b,&h,&t);

x=a;

y=b;

printf("\n x \t y \t");

while(x

{

k=h\times fun(x,y);

y=y+k;

x=x+h;

printf("%0.3f\t%0.3f\n",x,y);

}

}

which will give required answer y(2.5)=, correct upto four desimal places.

6 0
3 years ago
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