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kozerog [31]
3 years ago
5

For the trigonometric function shown below, what is midline, amplitude and the period in radians f(x) = 2 cos x /8f(x)=2cosx/8

Mathematics
1 answer:
artcher [175]3 years ago
5 0

Answer:

Step-by-step explanation:

mid line y=0 or x-axis

amplitude=2

for period

x/8=2π

x=16π

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almond37 [142]

Answer:

Area = 71.3 sq unit

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vectors

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CD = C - D = (4, -2 , -1) - (3, 4 , -4) = (1 , -6 , 3)

Hence we can see  that AB //CD and AD // BC as their unit vector co-efficents are identical/scalar multiple of each other.

b)

Equation of line AB = (1,1,3) + t*(-1 , 6 , -3 )

Point E = (1-t , 1+6t , 3 -3t) ... denotes an position of point E on line AB.

Choose a point on line CD, lets suppose C = ( 4 , -2 , -1 )

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For EC to be perpendicular to AB then dot product of AB . EC = 0

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t = -3/2

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Area = magnitude (AB) * magnitude (EC)

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Area = sqrt (46) * sqrt (442) / 2

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3 years ago
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Question in Picture.
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Answer:

The correct answer would be C

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