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3 years ago

Identify the values that create ordered pairs that are solutions to the equation 3x-5y=20

Mathematics

2 answers:

kvasek [131]3 years ago

8 0

The answer to your question is: x=10. y=2

IrinaVladis [17]3 years ago

3 0

Answer:

$(5,-1)$

$(10,2)$

Step-by-step explanation:

we have

The ordered pairs that are solutions to the equation $3x-5y=20$ are

$(5,y),(x,2)$

Step 1

Substitute the value of x of the first ordered pair and solve for y in the equation

$3(5)-5y=20$

$5y=15-20$

$y=-1$

The first ordered pair is $(5,-1)$

Step 2

Substitute the value of y of the second ordered pair and solve for x in the equation

$3x-5(2)=20$

$3x=20+10$

$x=10$

The second ordered pair is $(10,2)$

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4 years ago

A device produces random 64-bit integers at a rate of one billion per second. After how many years of running is it unavoidable

nikitadnepr [17]

Answer:

3171 × 10^(44) years

Step-by-step explanation:

For each bit, since we are looking how many years of running it is unavoidable that the device produces an output for the second time, the possible integers are from 0 to 9. This is 10 possible integers for each bit.

Thus, total number of possible 64 bit integers = 10^(64) integers

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3 years ago

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grandymaker [24]

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11 is 180-145= 35 degrees

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