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3 years ago

6

What is a pessimist's blood type?

2 answers:

Shalnov [3]3 years ago

8 0

B- (B negative) not ( Be negative) wink* wink*

jarptica [38.1K]3 years ago

5 0

Answer:

B-Negative

Step-by-step explanation:

Classic

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Find the instantaneous rate of change of the surface area s ! 6x2 of a cube with respect to the edge length x at x ! a

joja [24]

The instantaneous rate of change is simply equivalent to the first derivative of the equation or function. We are given the equation of Surface Area (A) with respect to side (x):

A = 6 x^2

Taking the first derivative of the equation:

dA = 12 x dx

dA / dx = 12 x

Now the term dA / dx is the instantaneous rate of change in the surface area with respect to the side length. To get the rate of change when the side x = a, simply plug this in into the equation:

rate of change = dA / dx = 12 x

so when x = a:

<span>rate of change = 12 a</span>

7 0

3 years ago

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which statements are true about the graph of the function f(x) = 6x – 4 x2? check all that apply. the vertex form of the functio

Brut [27]

Answer:

The vertex of the function is the point $(-3,-13)$

The graph increase over the interval--------> (-3,∞)

Step-by-step explanation:

we have

$f(x)=6x-4+x^{2}$

<u>1) Convert to vertex form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+4=x^{2}+6x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)+4+9=x^{2}+6x+9$

$f(x)+13=x^{2}+6x+9$

Rewrite as perfect squares

$f(x)+13=(x+3)^{2}$

$f(x)=(x+3)^{2}-13$ -----> function in vertex form

<u>2) Find the vertex</u>

The vertex of the function is the point $(-3,-13)$

<u>3) Find the axis of symmetry</u>

we know that

In a vertical parabola, the axis of symmetry is equal to the x-coordinate of the vertex

The x-coordinate of the vertex in this problem is equal to $x=-3$

therefore

the equation of the axis of symmetry is $x=-3$

<u>4) Find the increase-decrease intervals</u>

The graph increase over the interval--------> (-3,∞)

The graph decrease over the interval--------> (-∞,-3)

see the attached figure to better understand the problem

<u>5) Find the x-intercepts of the function</u>

we know that

the x-intercepts are the values of x when the value of the function is equal to zero

In this problem the x-intercepts are

$(-6.61,0)$ and $(0.61,0)$

so

The function cross the x-axis twice

see the attached figure

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4 years ago

Read 2 more answers

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Anuta_ua [19.1K]

Answer:

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Step-by-step explanation:

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3 years ago

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GalinKa [24]

Answer:

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Step-by-step explanation:

starting point : 800

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3 years ago