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SIZIF [17.4K]
2 years ago
14

Which of these is an example of qualitative data?

Mathematics
1 answer:
nordsb [41]2 years ago
5 0

i think it depends on if you have enough money to buy the books you need so C would be the answer

You might be interested in
A) What is the lower quartile of the data represented in the following box-and-whisker plot?
vovikov84 [41]
The lower quartile is 24 and the range is 35-22=13.....hope this helps
6 0
3 years ago
A single gram of a certain metallic substance has 0.52 g of copper and 0.25 g of zinc the remaining portion of the substance is
andrezito [222]
Ben's estimate gives 7 g of nickel; the actual amount is 8.03 g.

In 1 g of the substance, there is 0.52 g of copper and 0.25 g of zinc; this gives 
0.52+0.25 = 0.77 g of the substance.

The remaining part of the substance is nickel:
1-0.77 = 0.23 g of nickel.

Using Ben's estimate, 0.2 g of nickel per gram of substance, we have
0.2(35) = 7 g of nickel in 35 g of the substance.

The actual amount is 0.23(35) = 8.03 g of nickel in 35 g of the substance.
6 0
3 years ago
PLS PLS PLS PLS HELP ITS EASY111 BRAINLIEST POINTS
shusha [124]

Answer:

I think it's A

Step-by-step explanation:

6 0
2 years ago
Write a number in which the value of the 3 is ten times greater than the value of the 3 in 135, 864
Aleonysh [2.5K]

Answer:

345,456

Step-by-step explanation:

The value of 3 in 135,864 is 30,000.

We want to write a number that is ten times 30,000.

We could write any other number in which the value of 3 is 300,000.

There are infinitely many numbers that we can write.

Some examples are:

345,456

1,315,445

5,354,456

and so on and so forth.

8 0
3 years ago
Use the euclidean algorithm to find
kvasek [131]
A)
18=1\cdot12+6
12=2\cdot6+0
\implies\mathrm{gcd}(12,18)=6

b)
201=1\cdot111+90
111=1\cdot90+21
90=4\cdot21+6
21=3\cdot6+3
6=2\cdot3+0
\implies\mathrm{gcd}(111,201)=3

c)
1331=1\cdot1001+330
1001=3\cdot330+11
330=30\cdot11+0
\implies\mathrm{gcd}(1001,1331)=11

d)
54321=4\cdot12345+4941
12345=2\cdot4941+2463
4941=2\cdot2463+15
2463=164\cdot15+3
15=5\cdot3+0
\implies\mathrm{gcd}(12345,54321)=3

e)
5040=5\cdot1000+40
1000=25\cdot40+0
\implies\mathrm{gcd}(1000,5040)=40

f)
9888=1\cdot6060+3828
6060=1\cdot3828+2232
3828=1\cdot2232+1596
2232=1\cdot1596+636
1596=2\cdot636+324
636=1\cdot324+312
324=1\cdot312+12
312=26\cdot12+0
\implies\mathrm{gcd}(9888,6060)=12
8 0
3 years ago
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