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Alex787 [66]
3 years ago
11

You are building a rectangular dog pen with an area of 90ft^2. You want the length to be 3 ft longer that twice it's width. What

equation would you use to find the width of the pen?
Mathematics
1 answer:
Alecsey [184]3 years ago
8 0
I think the answers is the you think is if you think okayω
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The vertices of ΔABC are A(2, -5), B (-3, 5), and C (3, -3). The triangle is reflected over the x-axis. Use arrow notation to de
Artyom0805 [142]
Reflected over the x-axis: A'(2,-5),B'(-3,-5),C'(3,3)<span>. Hence, the original triangle is described by A'B'C'.</span>
8 0
3 years ago
Read 2 more answers
Is this right or wrong ?
Otrada [13]

Answer:

(3x - 2)(4x + 6) = 12 {x}^{2} + 18x - 8x + - 12 \\  = 12 {x}^{2} + 10x - 12

6 0
3 years ago
How do I factor 2x^3−18x and x ^3+6x^2+8x
Nana76 [90]

Answer:

2x(x − 3)(x + 3)

x(x + 4)(x + 2)

Step-by-step explanation:

2x³ − 18x

x(2x² − 18)

2x(x² − 9)

2x(x − 3)(x + 3)

x³ + 6x² + 8x

x(x² + 6x + 8)

x(x + 4)(x + 2)

4 0
3 years ago
Please Help Me! I will give all my point to who ever answers my question!!!
love history [14]

Step-by-step explanation:

The equation that is given is only for the specific place of that object. To find the velocity, you need to take the derivative of the equation. This will give you:

V=2+\frac{1}{2} t

Now, to find the average velocity of this object, plug in the values given to you. It's between the time interval [1, 2] so these are the two numbers you'll plug into the velocity equation. Finding this average is like finding any other average.

So

V(1)=2+\frac{1}{2} (1)\\V(1)=2+\frac{1}{2}=\frac{5}{2}\\V(2)=2+\frac{1}{2}(2)\\V(2)=2+1=3

V_{avg}=\frac{3-\frac{5}{2} }{2-1} \\V_{avg}=\frac{\frac{6}{2}-\frac{5}{2}  }{1} \\V_{avg}=\frac{1}{2}

Average velocity is 0.5 sec

To find instantaneous velocity just find the velocity at time one. Think about the name "instantaneous velocity," it's the velocity in that <u>instant</u>.

We already found this, so I don't need more work (it's displayed above).

The instantaneous velocity when t=1 is 2.5 sec.

3 0
3 years ago
If m∠NLO = 41° and m∠NLM = 88°, what is m∠OLM?
puteri [66]

Answer:

47°

Step-by-step explanation:

Given that m<NLO = 41°, and m<NLM = 88°, according to angle addition postulate, m<OLM + m<NLO = m<NLM

Therefore, subtracting m<NLO from both sides will give us:

m<OLM = m<NLM - m<NLO

m<OLM = 88° - 41°

m<OLM = 47°

5 0
3 years ago
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