Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p
a. 1/2
b. 2 times
c. 1/4
d. 4 times
Answer:
4 times
Step-by-step explanation:
Given the following :
Distance between q and S (r) = 1 unit
Distance between P and S (r) = 2 × 1 unit = 2
According to coliumbs law:
F = Ke(q1q2) /r^2
Where F = electrostatic force, Ke = coloumbs constant
q1,q2 = charges, r = distance between two charges
For q and S :
Fsq = Ke(q1q2) / 1^2
Fsq = Ke(q1q2) - - - - - equation 1
For P and S :
Fsp = Ke(q1q2) / 2^2
Fsp = Ke(q1q2) / 4 - - - - - equation 2
Dibiding equation 1 by equation 2
Fsq/Fsp = Ke(q1q2) / Ke(q1q2)/4
Fsq / Fsp = Ke(q1q2) × 4 / Ke(q1q2)
Fsq / Fsp = 4 / 1
Using cross multiplication
Therefore, Fsq = 4 × Fsp
Answer:
Obviously, Juan because he played less game last season and got the same amount of points so this season when he plays more games he would get more points than Neil
Leslie:
h= hours
3/4h=4 1/2 laps
divide both sides by 3/4 or .75
1 hour = 6 laps
Kayla:
3/4h= 3 1/2 laps
divide both sides by 3/4
1 hour = 4 2/3 laps
Leslie can do C
1_ 1/3 more laps in an hour than Kayla
Answer:
3x^2 +8x +3
Step-by-step explanation:
(6x^2 + 8x - 3) - (3x^2 - 6)
Distribute the minus sign
(6x^2 + 8x - 3) - 3x^2 + 6
Combine like terms
3x^2 +8x +3
Answer:
3
Step-by-step explanation:
