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creativ13 [48]
3 years ago
15

figure PQRS is a parallelogram. What are the measures of angles P and S? ∠P = 20°; ∠S = 160° ∠P = 40°; ∠S = 140° ∠P = 140°; ∠S =

40° ∠P = 160°; ∠S = 20°
Mathematics
2 answers:
MaRussiya [10]3 years ago
8 0

Answer:

c

Step-by-step explanation:

viktelen [127]3 years ago
4 0
I believe it is C (p=140 s=40)
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Alina [70]
DB/dt = k*B
dB/(kB) = dt
Integrating both sides:
1/k*ln|B| = t + C
B = C*e^(kt)
At time t = 0, B = 4000 and at time t = 3 (3 hours past 9 AM), B = 4500
4000 = C
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3 years ago
Mr. Campbell was travelled 80 miles in 2 hours. What was his average speed?
Mamont248 [21]
His average speed is 40mph you get your answer by dividing 80 by 2, or or you could do what is half of 80 which is 40. So Mr.Campbell average speed is 40mph
4 0
3 years ago
How do you plot f(x)= (x + 4) ^2
UkoKoshka [18]

I hope this helps please tell me if it doesn’t

6 0
4 years ago
A company has two manufacturing plants with daily production levels of 7 x plus 19 items and 2 x minus 7 ​items, respectively. T
leva [86]

First plant produces 5x+26 items more than second plant daily

Step-by-step explanation:

Given

The expression for plant A will be:

7x+19

For plant B:

2x-7

In order to find that how much more items are produced by first plant we have to subtract the daily production of second plant from first plant

So,

= 7x+19-(2x-7)\\= 7x+19-2x+7\\= 7x-2x+19+7\\=5x+26

So,

First plant produces 5x+26 items more than second plant daily

Keywords: Polynomials, expressions

Learn more about polynomials at:

  • brainly.com/question/729447
  • brainly.com/question/7287774

#LearnwithBrainly

5 0
3 years ago
The manufacturer of an airport baggage scanning machine claims it can handle an average of 560 bags per hour. (a-1) At α = .05 i
ioda

Answer:

The calculated value t = 1.76 < 2.131 at 0.05 level of significance

Null hypothesis is accepted

The manufacturer’s claim is greater than 560 bags per hour

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given sample size 'n' =16

Given the manufacturer of an airport baggage scanning machine claims it can handle an average of 560 bags per hour.

mean of the Population 'μ' = 560

Mean of the sample Χ⁻ = 538

sample standard deviation' S' = 50

<em><u>Null hypothesis</u></em><em>:H₀:μ > 560</em>

<em><u>Alternative Hypothesis</u></em><em>:H₁ : :μ < 560 (left tailed test)</em>

<em>Test statistic</em>

   t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }

  t = \frac{538-560 }{\frac{50}{\sqrt{16} } } = -1.76

|t| = |-1.76| = 1.76

<em>Degrees of freedom </em>

<em>γ = n-1 =16-1 =15</em>

t_{\frac{\alpha }{2} } = t_{\frac{0.05}{2} } =t_{0.025} =2.131

<em><u>Conclusion</u></em>:-

The calculated value t = 1.76 < 2.131 at 0.05 level of significance

Null hypothesis is accepted

The manufacturer’s claim is greater than 560 bags per hour

6 0
4 years ago
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