Question

A student is taking two courses, history and math. The probability the student will pass the history course is 0.60, and the probability of passing the math course is 0.70. The probability of passing both is 0.50. What is the probability of passing at least one

Answer 1

Answer:

The probability that students will passing at least on course=0.80.

Step-by-step explanation:

We are given that  a student is taking two courses, history and math.

The probability the student will pass the history course =P(A)=0.60

The probability that the student will pass the math course=P(B)=0.70

The probability that the students will pass the both course=$P(A\cap B)=0.50$

We have to find the probability that student passing at least one course.It means we have to find the probability of $(A\cup B)$

We know that formula

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Using the formula we get

$P(AUB)=0.60+0.70-0.50=0.80$

The probability that students will passing at least on course=0.80.