3 years ago

what is the probability of having one girl and three boys in a 4 child family assuming boys and girls are equally likely

1 answer:

5 0

The possibilities are:

bbbb

bbbg

bbgg

bggg

This shows that there is a 1 in 4 chance of having three boys and one girl

So the answer could be 1/4 or a 25% chance

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Use commutative property of addition to collect like terms 23y-(7x-2y)+x

oksano4ka [1.4K]

The like terms are 23y & 2y and 7x & x because they have the same variables

5 0

3 years ago

14.7x11.361 how do I solve this problem?

horrorfan [7]

167.0067 is the correct answer

8 0

3 years ago

Jada has a stand in the marketplace where she sells ground cumin. Her weekly expenses are $300, and she sells her cumin at a fix

Black_prince [1.1K]

Answer:

$7.5

40 kg

Step-by-step explanation:

Expenses= $300 per week

120x= 300+600

120x=900

x= 900/120= $7.5 per kg

300/7.5= 40 kg to be sold to cover weekly expenses

4 0

3 years ago

What is the solution to 1.6m-4.8m=-1.6m?

Aleksandr [31]

Answer:

m=0

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

7 0

3 years ago

If f(x) = -x + 5 and g(x) = x^2, what is (g° (-1)?

ipn [44]

Answer:

$(g\circ f)(-1)=36$

Step-by-step explanation:

We are given the two functions:

$f(x)=-x+5\text{ and } g(x)=x^2$

And we want to find:

$(g\circ f)(-1)$

This is equivalent to:

$=g(f(-1))$

So, evaluating f(-1) first, we acquire:

$f(-1)=-(-1)+5=6$

Then by substitution:

$=g(6)$

So:

$=(6)^2=36$

Therefore:

$(g\circ f)(-1)=36$

Your answer is indeed correct.

7 0

3 years ago

Read 2 more answers