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3 years ago

Which of the following values cannot be probabilities? 3/5, 5/3, 0, 1, 1.15, StartRoot 2 , -0.57, 0.09

Mathematics

1 answer:

Ugo [173]3 years ago

7 0

Answer:

$\sqrt{2},-0.57$

Step-by-step explanation:

Probability of any incidence can only be a rational number.

Porbability can never be less than zero. It is basically defined as the ratio of

chance of occurence of an event to the total possible ways of occurence of the event. So an event cannot occur and the probability can be zero but never negative.

$\sqrt{2}$ being a irrational number cannot be a possibkle vlue for probability.

Hence values which cannot be possible are $\sqrt{2},-0.57$ .

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Answer:

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Step-by-step explanation:

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3 years ago

Which represents a quadratic function? f(x) = −8x3 − 16x2 − 4x f (x) = x 2 + 2x − 5 f(x) = + 1 f(x) = 0x2 − 9x + 7

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3 years ago

Equation for the given function

Lera25 [3.4K]

Answer:

Step-by-step explanation:

hello :

g(x) = (x+2)(x-4)/(x+2)(x-1)

1 ) this function no exist for if : x= -2 and 1

so the denominater is : (x+2)(x-1)

so : b= 2 and c=1

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so the numerater is : (x+2)(x-4)

g(x) =0 if : (x+2)(x-4)=0

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note :

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3 years ago

What is the name of the relationship between ∠1 and ∠5?

kompoz [17]

Answer:

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Step-by-step explanation:

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3 years ago

Which of the following values cannot be​ probabilities? 3/5​, 5/3​, 0​, 1​, 1.15​, StartRoot 2 , -0.57​, 0.09

Which of the following values cannot be probabilities? 3/5, 5/3, 0, 1, 1.15, StartRoot 2 , -0.57, 0.09