Which of the following values cannot be probabilities? 3/5, 5/3, 0, 1, 1.15, StartRoot 2 , -0.57, 0.09

Mathematics

1 answer:

Ugo [173]4 years ago

7 0

Answer:

$\sqrt{2},-0.57$

Step-by-step explanation:

Probability of any incidence can only be a rational number.

Porbability can never be less than zero. It is basically defined as the ratio of

chance of occurence of an event to the total possible ways of occurence of the event. So an event cannot occur and the probability can be zero but never negative.

$\sqrt{2}$ being a irrational number cannot be a possibkle vlue for probability.

Hence values which cannot be possible are $\sqrt{2},-0.57$ .

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Answer:

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Step-by-step explanation:

Step 1: Simplify both sides of the equation.

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15 + - 4y = - 21 + - y

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Step 2: Add y to both sides.

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Step 3: Subtract 15 from both sides.

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I am so sorry if it is long and confusing, but, I hope this still helps!

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