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ch4aika [34]
3 years ago
8

Which of the following values cannot be​ probabilities? 3/5​, 5/3​, 0​, 1​, 1.15​, StartRoot 2 , -0.57​, 0.09

Mathematics
1 answer:
Ugo [173]3 years ago
7 0

Answer:

\sqrt{2},-0.57

Step-by-step explanation:

Probability of any incidence can only be a rational number.

Porbability can never be less than zero. It is basically defined as the ratio of

chance of occurence of an event to the total possible ways of occurence of the event. So an event cannot occur and the probability can be zero but never negative.

\sqrt{2} being a irrational number cannot be a possibkle vlue for probability.

Hence values which cannot be possible are \sqrt{2},-0.57.

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1. 12 = x + 3<br> 2. b+0.6= -1<br> 3. a+(-4)= -13<br> 4. x+27= -12<br> 5. a+(-1.2)= -5.5
Archy [21]
1. 12=x+3    12-3=9  now try 9+3 that is 12 so x=9
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What does x equal in -7=-1+x/3
Scorpion4ik [409]

Hello! :)

To solve your equation, we will first simplify both sides of the equation

-7 = -1 + x/3

-7 = -1 + 1/3x

-7 = 1/3x - 1

Next, we will flip the equation

1/3x - 1 = -7

Third, we will add 1 to both sides

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Last, we will Multiply both sides by 3

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x = -18 (ANSWER)

That means -18 is you answer

Hope this helped you!

THEDIPER

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