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ch4aika [34]
4 years ago
8

Which of the following values cannot be​ probabilities? 3/5​, 5/3​, 0​, 1​, 1.15​, StartRoot 2 , -0.57​, 0.09

Mathematics
1 answer:
Ugo [173]4 years ago
7 0

Answer:

\sqrt{2},-0.57

Step-by-step explanation:

Probability of any incidence can only be a rational number.

Porbability can never be less than zero. It is basically defined as the ratio of

chance of occurence of an event to the total possible ways of occurence of the event. So an event cannot occur and the probability can be zero but never negative.

\sqrt{2} being a irrational number cannot be a possibkle vlue for probability.

Hence values which cannot be possible are \sqrt{2},-0.57.

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Answer:

<em>z-score will be:  7.741....  and it will be unusual. </em>

Step-by-step explanation:

Human body temperatures have a mean of 98.20 degrees Fahrenheit and a standard deviation of 0.62 degrees Fahrenheit.

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z(X=103.00)= \frac{103.00-98.20}{0.62}=7.741...

As, here the z-score is more than 2 standard deviations above the mean, so 103.00 degrees Fahrenheit is unusual for human body temperature.

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