Answer: 168 inches.
Explanation:
First thing you must always do when solving word problems is read closely, and take note of any number.
In this case, the first thing we must do is find the scale factor.
For this, we use one of the dimensions. We will use the width of the photo.
We have then:
k = 132/11
k = 12
Then, we look for the value of the height of the new photo. To do this, we multiply the scale factor by the original dimension.
We have then:
14k = 14 (12) = 168
Thus, 168 inches is your answer! :)
Hope this helps! :)
Answer:
See answer below
Step-by-step explanation:
The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.
i) x∈AnB if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.
ii) (I will abbreviate "if and only if" as "iff")
x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.
iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).
iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).
The volume of the solid objects are 612π in³ and 1566πcm³
<h3>Volume of solid object</h3>
The given objects are composite figures consisting of two shapes.
The volume of the blue figure is expressed as;
Volume = Volume of cylinder + volume of hemisphere
Volume = πr²h + 2/3πr³
Volume = πr²(h + 2/3r)
Volume = π(6)²(13+2/3(6))
Volume = 36π(13 + 4)
Volume = 612π in³
For the other object
Volume = Volume of cylinder + volume of cone
Volume = πr²h + 1/3πr²h
Volume = π(9)²(15) + 1/3π(9)²(13)
Volume= 81π (15+13/3)
Volume= 1566πcm³
Hence the volume of the solid objects are 612π in³ and 1566πcm³
Learn more on volume of composite figures here: brainly.com/question/1205683
#SPJ1
(x−a)(x−b)
=(x+−a)(x+−b)
=(x)(x)+(x)(−b)+(−a)(x)+(−a)(−b)
=x2−bx−ax+ab
<h2><u><em>
=ab−ax−bx+x2</em></u></h2>
600 centimeters > 5 meters
