All categories

3 years ago

Find the x value for point C such that AC and BC form a 2:3 ratio.

Mathematics

2 answers:

vekshin13 years ago

6 0

I believe it would be 4

igor_vitrenko [27]3 years ago

3 0

C would be the anser

You might be interested in

Theo started to solve the quadratic equation (x+2)2 - 9 = -5

Yuliya22 [10]

Answer:2x−5=−5

Add 5

to both sides of the equation.

2x=−5+5

Add −5

and 5

2x=0

Divide each term by 2

and simplify.

Divide each term in 2x=0

by 2

2x2=02

Cancel the common factor of 2

Cancel the common factor.

x2=02

Step-by-step explanation:

Apply the distributive property.

x⋅2+2⋅2−9=−5

Move 2

to the left of x

2⋅x+2⋅2−9=−5

Multiply 2

by 2

2x+4−9=−5

Subtract 9

from 4

3 0

3 years ago

What is 10% of 400.00

oee [108]

<span><span>If you want to evaluate what is 10 percent of 400, you can do this using the following few steps:</span><span>

10% * 400 = 10/100 * 400 = 0.1 * 400 = 40

<span>10% of 400 is 40.</span></span></span>

4 0

3 years ago

Read 2 more answers

Finding the Midpoint of the Two Coordinates<br> 6.) A(-2, 3), B(5,-1)

RoseWind [281]

Answer:

The answer is

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

$M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )\\$

From the question the points are

A(-2, 3), B(5,-1)

The midpoint is

$M = ( \frac{ - 2 + 5}{2} \: , \: \frac{3 - 1}{2} ) \\ = ( \frac{3}{2} \: , \: \frac{2}{2} )$

We have the final answer as

$( \frac{3}{2} \: , \: 1) \\$

Hope this helps you

8 0

4 years ago

The ratio of the perimeters of two similar triangles is 4:7. What is the area of each of these triangles if the sum of their are

Mashcka [7]

Answer:

The area of triangles are 16 cm^2 and 49 cm^2

Step-by-step explanation:

we know that

If two figures are similar, the ratio of its perimeters is equal to the scale factor and the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of the smaller triangle in square centimeters

y ----> the area of the larger triangle in square centimeters

we know that

$z=\frac{4}{7}$

$\frac{x}{y}=z^2$

$\frac{x}{y}=(\frac{4}{7})^2$

$\frac{x}{y}=\frac{16}{49}$

$x=\frac{16}{49}y$ -----> equation A

$x+y=65$ ----> equation B

solve the system by substitution

substitute equation A in equation B

$\frac{16}{49}y+y=65$

solve for y

$\frac{65}{49}y=65$

$y=49\ cm^2$

Find the value of x

$x=\frac{16}{49}(49)$

$x=16\ cm^2$

therefore

The area of triangles are 16 cm^2 and 49 cm^2

3 0

4 years ago

Read 2 more answers

I need help please!

hoa [83]

the correct answer is c

8 0

3 years ago