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2 years ago

You are randomly picking a number between 1 and 20, inclusive. What is the probability of selecting a

Mathematics

2 answers:

julsineya [31]2 years ago

5 0

Answer:

of favourable events = 4, (which includes 1, 4, 9, 16). And, total number of observations are 20. So, the probability of picking a square number between 1 and 20 is 1/5.

Step-by-step explanation:

andrey2020 [161]2 years ago

4 0

Answer:

Answer is 20% chance. (20/100 or 4/20)

Step-by-step explanation:

There are 4 perfect squares in a number set 1-20.

1,4,9, and 16.

So that is 4/20. I multiplied the fraction by 5 to get 20/100 to get 20%

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Refer to Table 4-4. If these are the only four sellers in the market, then the market quantity supplied at a price of $4 is

NeTakaya

All things being equal; demand decreases, as price increases.

The quantity supplied when price is $4 is 28

From table 4.4 (see attachment).

When price = $4, we have the following supplies:

Firm A = 6
Firm B = 6
Firm C = 8
Firm D = 10

So, the total supply at $4 is:

$Total = 4 + 6 + 8 + 10$

$Total = 28$

Hence, the quantity supplied when price is $4 is 28

Read more about demand and supply at:

brainly.com/question/13353440

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2 years ago

A Gallup poll of 1236 adults showed that 12% of the respondents believe that it is bad luck to walk under a ladder. Consider th

SOVA2 [1]

Answer:

Step-by-step explanation:

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3 years ago

ANSWER PLZ QUICK AND FAST

Digiron [165]

I believe it is C because I counted the dots in the shaded region.

Hope it is correct :)

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3 years ago

Please answer all of them! SHOW WORK!!

antiseptic1488 [7]

Wait I can help fm dm

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2 years ago

The number of books sold over the course of the four-day book fair were 190, 100, 272, and 74. Assume that samples of size 2 are

g100num [7]

Answer:

the answer is below

Step-by-step explanation:

We have the total number of possible samples = 4 * 4 = 16 (As 4 choices for each value)

in addition we have to as all sample occur with equal probability, probability of each sample = 1/16, below is samling distribution of mean

x1 x2 probabilityP(x1,x2) sample mean

190 190 1/16 190

190 100 1/16 145

190 272 1/16 231

190 74 1/16 132

100 190 1/16 145

100 100 1/16 100

100 272 1/16 186

100 74 1/16 87

272 190 1/16 231

272 100 1/16 186

272 272 1/16 272

272 74 1/16 173

74 190 1/16 132

74 100 1/16 87

74 272 1/16 173

74 74 1/16 74

Summarizing above with adding duplicate values

sample mean probability

74 1/16

87 1/8

100 1/16

132 1/8

145 1/8

173 1/8

186 1/8

190 1/16

231 1/8

272 1/16

5 0

3 years ago