All categories

2 years ago

You are randomly picking a number between 1 and 20, inclusive. What is the probability of selecting a

Mathematics

2 answers:

julsineya [31]2 years ago

5 0

Answer:

of favourable events = 4, (which includes 1, 4, 9, 16). And, total number of observations are 20. So, the probability of picking a square number between 1 and 20 is 1/5.

Step-by-step explanation:

andrey2020 [161]2 years ago

4 0

Answer:

Answer is 20% chance. (20/100 or 4/20)

Step-by-step explanation:

There are 4 perfect squares in a number set 1-20.

1,4,9, and 16.

So that is 4/20. I multiplied the fraction by 5 to get 20/100 to get 20%

You might be interested in

Solve the inequality.<br> −12−4x≤

disa [49]

Answer:

-4(3+x)

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Question 1

svetoff [14.1K]

Answer:

B.) 8x + 12

Step-by-step explanation:

Using the Distributive Property the 4 is multiplied by each number inside the parentheses

4*2x = 8x

4*3 = 12

8x+12

8 0

3 years ago

Read 2 more answers

Brainliest ,easy question

insens350 [35]

Answer:

Scale factor is 2/5 or 0.4

Step-by-step explanation:

Divide radius of smaller circle (2) by radius of large circle (5)

4 0

2 years ago

A contractor is required by a county planning department to submit one, two, three, four, five, or six forms (depending on the n

Ratling [72]

Answer:

$k = \dfrac{1}{21}$

b) 0.476

c) 0.667

Step-by-step explanation:

We are given the following in the question:

Y = the number of forms required of the next applicant.

Y: 1, 2, 3, 4, 5, 6

The probability is given by:

$P(y) = ky$

a) Property of discrete probability distribution:

$\displaystyle\sum P(y_i) = 1\\\\\Rightarrow k(1+2+3+4+5+6) = 1\\\\\Rightarrow k(21) = 1\\\\\Rightarrow k = \dfrac{1}{21}$

b) at most four forms are required

$P(y \leq 4) = \displaystyle\sum^{y=4}_{y=1}P(y_i)\\\\P(y \leq 4) = \dfrac{1}{21}(1+2+3+4) = \dfrac{10}{21} = 0.476$

c) probability that between two and five forms (inclusive) are required

$P(2\leq y \leq 5) = \displaystyle\sum^{y=5}_{y=2}P(y_i)\\\\P(2\leq y \leq 5) = \dfrac{1}{21}(2+3+4+5) = \dfrac{14}{21} = 0.667$

8 0

3 years ago

Three ice cream cones cost 8.25,at this rate how much does 2 ice creams cones cost for two cones

Sav [38]

Answer:

5.50

Step-by-step explanation:

If three cones cost 8.25, then each cone should cost 2.75. (8.25 / 3 = 2.75)

Then 2 cones should cost 5.50 (2.75 x 2 = 5.50)

5 0

3 years ago