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AleksAgata [21]
3 years ago
5

Name the image of F

Mathematics
1 answer:
Sloan [31]3 years ago
6 0
D, or <S, because if you reflect, rotate, and translate shape CDEF, it would form shape TQRS and < F would fit right into <S. Hope this helps!
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Brian's gross earnings for the week of July 8, 2019, are $1227.38. His deductions comprise 23% of his total compensation.
artcher [175]

Question is Incomplete;Complete question is given below;

Brian's gross earnings for the week of July 8, 2019, are $1227.38. His deductions comprise 23% of his total compensation.

What is his net pay?

Enter the answer to the nearest hundredth, such as $1234.56.

Answer:

Brian's Net pay is $945.08.

Step-by-step explanation:

Given:

Gross earnings for the week = $1227.38

Deductions = 23%

We need to find the net pay.

Solution:

First we will find the amount deducted.

amount deducted is equal to Deductions on Gross pay.

framing in equation form we get;

amount deducted = \frac{23}{100}\times 1227.38 = \$282.2974

Now we can say that;

Net pay is equal to Gross earnings minus amount deducted in tax.

framing in equation form we get;

Net pay = 1227.38-282.2974 = \$945.0826

Rounding to nearest hundred  we get;

Net pay = $945.08

Hence Brian's Net pay is $945.08.

6 0
3 years ago
Daniel reads dor 8 times as many as April. Daniel read 44 minutes this week. How many minutes does April read?
ELEN [110]
44 [minutes] * 8 [times as many as April] = 352 [minutes in April]
5 0
3 years ago
Ind the area of the rectangle, in square centimeters. Rectangle ABCD Length = 20 cm Width = 9 cm​
alexdok [17]

Answer:

180 cm^3

Step-by-step explanation:

A=lw

A=20×9

A=180

4 0
3 years ago
What Is 1+1=? Help!!!
mestny [16]
2!!! I better get 5 points
4 0
3 years ago
Read 2 more answers
Find the first three iterates of the function f(z) = z2 + c with a value of c = 2 - 3i and an initial value of z0 = 1 + 2i.
Artist 52 [7]

Answer:

C

Step-by-step explanation:

We have: (I rewrote the function)

f(z_n)={z_{n-1}} ^2+c

Given that:

\displaystyle c=2-3i \text{ and } z_0 = 1 + 2 i

The first iterate will be:

\displaystyle \begin{aligned} f(z_1)&=(z_0)^2+c \\ &=(1+2i)^2+(2-3i) \\ &= (1+4i+4i^2)+(2-3i) \\ &=1+4i-4+2-3i \\ &=-1+i \end{aligned}

The second iterate will be:

\begin{aligned}f(z_2) &=(z_1)^2+c\\ &=(-1+i)^2+(2-3i) \\&= (1-2i+i^2)+(2-3i) \\&=1-2i-1+2-3i \\&=2-5i \end{aligned}

And the third iterate will be:

\begin{aligned} f(z_3)&=(z_2)^2+c\\ &=(2-5i)^2+(2-3i) \\ &=(4-20i+25i^2)+(2-3i) \\ &=4-20i-25+2-3i \\ &=-19-23i \end{aligned}

Hence, our answer is C.

3 0
3 years ago
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