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Dmitry [639]
3 years ago
14

Write the equation of the line that perpendicular to 4x+5y=20 an that passes through the point (-4,1)

Mathematics
1 answer:
Bad White [126]3 years ago
6 0

Answer:

y = (5/4)x + 6

Step-by-step explanation:

The 1st line's equation is:

● 4x + 5y = 20

Substract 4x from both sides

● 4x + 5y - 4x = 20 - 4x

● 5y = 20 -4x

● 5y = -4x + 20

Divide both sides by 5

● 5y/5 = (-4x + 20)/5

● y = (-4/5)x + 4

● y = -0.8x + 4

Let m be the slope of the second line

The lines are perpendicular so the product of their slopes equals -1

Then: m × (-0.8) = -1

● m × (-0.8)= -1

● m = -1/(-0.8)

● m = 1.25

y = 1.25x + b

b is the y-intercept of the line.

To get it replace by the coordinates of a point.

We are given that the line passes through (-4,1)

● y = 1.25x + b

● 1 = 1.25 × (-4) + b

1.25 is 5/5

● 1 = (5/4) × (-4) + b

● 1 = -5 + b

Add 5 to both sides

● 1 + 5 = -5 + b + 5

● b = 6

So the equation is

● y = (5/4)x + 6

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Jerome recently moved to a new city and bought a home. The assessment rate is 51%. The property tax rate is $53.26 per $1000. Wh
mrs_skeptik [129]
Given:
assessment rate = 51%
tax rate = 53.26 per 1,000

53.26 / 1000 = 0.05326
0.05326 x 100% = 5.326%

Effective tax rate = assessment rate * tax rate
ETR = 51% * 5.326%
ETR = 2.72%



8 0
3 years ago
One parent is a cystic fibrosis carrier, and the other has
Marysya12 [62]

Answer:

A - 0%

B- 50%

C- 50%

D- 100%

Step-by-step explanation:

Cystic fibrosis is inherited in an autosomal recessive form, meaning that a person has to inherit two abnormal genes for the disease to manifest. In the case of this question, one parent is a gene carrier, so his genotype is Aa, while the other does not have the cystic fibrosis gene, so AA.

Performing the cross of Aa x AA, we can see that:

a.) The probability of a child would have cystic fibrosis is 0%, since the disease is recessive and to be affected it should receive a recessive gene from each parent.

b.) The probability of a child would be a carrier is 50%, as 50% of the crossing phenotypes are Aa.

c.) The probability of a child would not have cystic fibrosis and is not a carrier is 50%, as 50% of the child's genotype is AA.

d.) The probability of a child would be healthy is 100%, as of all possible phenotypes none is affected.

5 0
3 years ago
Help please me!!!!!!!!!!!
AlexFokin [52]
D:  We solve this in exactly the same way in which we solved the previous area problem.  Side length is s, area is s^2.  Here, side length is 5 in; area is 25 in^2.
the problem does say, however, not to include units in your answer.  Thus, just write "25."
5 0
2 years ago
Read 2 more answers
Let f(x)=x+a/x+b such that f(f(1)=0 & f(2)=-3 then a&b resctivily are.
Yuliya22 [10]

Answer:

The value of a = - 1  ,   And b = \frac{ - 7 }{3}    

Step-by-step explanation:

Given as :

Function f(x) = \frac{(x + a)}{(x + b)}

And f(f(1)) = 0     And f(2) = - 3

Now For , x = 2 , y = - 3

I.e  f(2) = \frac{(2 + a)}{(2 + b)}

or,  - 3 = \frac{(2 + a)}{(2 + b)}

I.e 2 + a = - 6 - 3b

Or, a + 3b = - 8               ....... 1

Again  f(f(1)) = 0

So,  \frac{(1 + a)}{(1 + b)} = 0

Or,  1 + a = 0

∴    a = - 1

So , put htis value of a i n eq 1 , we get value of  b

So , - 1 + 3b = - 8

Or,   3b = - 7

∴       b = \frac{ - 7 }{3}

Hence The value of a = - 1  ,   And b = \frac{ - 7 }{3}    Answer

3 0
3 years ago
HELP PLSSS<br><br> find f(9) if f(x) = 4^x + 12
Anna35 [415]

Answer:

I think its 262156

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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