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jek_recluse [69]
3 years ago
6

Lateral and surface area of prisms?

Mathematics
1 answer:
nekit [7.7K]3 years ago
6 0

Answer:

Lateral surface area is the round part/the middle part of the cylinder, not the bases

Step-by-step explanation:

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Algebra 2 help. Solving equations containing two radicals
Marysya12 [62]

These are 3 questions and 3 answers.

Question 1.

Answer: bot equations have the same potential solutions, but equation A may have extraneous solutions

Explanation:

1) Equation A

\sqrt{x^2+3x-6}=\sqrt{x+2}\\ \\  x^2+3x-6=x+2\\ \\  x^2+2x-8=0\\ \\  (x+4)(x-2)=0\\ \\  x=-4 ; x =2

Replace x = -4 in the right side of the equation:

\sqrt{x+2} =\sqrt{-4+2} =\sqrt{-2}

Which is not defined, so this is a extraneous solution.

2) Equation B.

Since it is a cube root, it is defined for any (negative, zero, and positive) values of x.

Question 2.

Answer: cubing both sides once.

Explanation:

\sqrt[3]{5x-2} -\sqrt[3]{4x} =0\\ \\  \sqrt[3]{5x-2} =\sqrt[3]{4x}\\  \\  (\sqrt[3]{5x-2} )^3=(\sqrt[3]{4x})^3\\  \\  5x-2=4x\\ \\  5x-4x=2\\ \\  x=2

3) Question 3.

Answer: c - 2 = 25 + c + 10√c

Explanation:

\sqrt{c-2} -\sqrt{c} =5\\ \\ \\  \sqrt{c-2} =\sqrt{c} +5\\ \\  (\sqrt{c-2})^{2}  =(\sqrt{c}+5)^2\\  \\  c-2=c+10\sqrt{c} +25\\ \\  c-2=25+c+10\sqrt{c}

4 0
3 years ago
I need help on this math question please
tiny-mole [99]

Answer:

2.68

Step-by-step explanation:

4 0
3 years ago
What is the area of the trapezoid?<br> A) 176 cm^2<br> B)192 cm^2<br> C)208 cm^2<br> D)224 cm^2
LenKa [72]

Answer:

a

Step-by-step explanation:

.

3 0
3 years ago
1. What is the value of the expression<br> 4X (4 – 2) + 6?
Snezhnost [94]

Answer:

8x+6

Step-by-step explanation:

4x (4-2)=2

4X*2+6

8x+6

6 0
4 years ago
Read 2 more answers
Please help me with 7 and 9 I’m really confused and I really need help!!
Margarita [4]

Answer:

  7) K'(1, 1), N'(4, 0), Q'(4, 4)

  9) F'(4, 2), W'(4, 5), K'(3, 2)

Step-by-step explanation:

When you are not sure about reflections and rotations, it can be useful to actually draw a graph. The line of reflection is the perpendicular bisector of the segment connecting a point with its image. That is, the image is the same distance from the line on the other side. A point that is <em>on</em> the line of reflection is "invariant," it doesn't move.

__

7) Reflecting across the x-axis changes the sign of the y-coordinate. That is all. Any point on the x-axis (y=0) is unchanged. The transformation is ...

  (x, y) ⇒ (x, -y)

__

9) Reflecting across a vertical line changes the x-coordinate. The new value of x will be ...

  x' = 6 - x

The "6" is double the x-coordinate of the vertical line. The transformation is ...

  (x, y) ⇒ (6-x, y)

_____

<em>Derivation of the formula for reflection on x=3</em>

In general if M is the midpoint of a point (A) and its reflection (A'), then we have ...

  M = (A +A')/2

  2M = A + A'

  2M -A = A'

When a point is reflected across a vertical line, all of the y-coordinate values remain unchanged. So, for A=(x, y) and M=(3, y), we have ...

  A' = 2(3, y) -(x, y) = (6-x, 2y-y)

  A' = (6 -x, y)

So, the reflection transformation across the line x = 3 is ...

  (x, y) ⇒ (6-x, y)

6 0
3 years ago
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