OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
Remark
Don't try and do this all at once. Break it down, otherwise you'll have layers and brackets all over the place.
Step One
Find 23/0.3
X = 23/0.3 = 76.7
Step Two
Now Divide by 20
x1 = 76.7 / 20
x1 = 3.83
Step Three
Take this result and put it over 24
x2 = x1/24
x2 = 3.83 / 24
x2 = 0.1597 <<<< Answer
Inflection point is the point where the second derivative of a graph is zero.
y = (x+1)arctan xy' = (x+1)(arctan x)' + (1)arctan xy' = (x+1)/(x^2+1) + arctan xy'' = (x+1)(1/(1+x^2))' + 1/(1+x^2) + 1/(1+x^2)y'' = (x+1)(-1/(1+x^2)^2)(2x)+2/(1+x^2)y'' = ((x+1)(-2x)+1+x^2)/(1+x^2)^2y'' = (-2x^2-2x+2+2x^2)/(1+x^2)^2y'' = (-2x+2)/(1+x^2)^2
Solving for point of inflection: y'' = 00 = (-2x+2)/(1+x^2)^20 = -2x+2x = 1y(1) = (1+1)arctan(1) = 2 * pi/4 = pi/2
Therefore, E(1, pi/2).
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Answer:
In think is the first one
Answer:
(- 3, - 5 )
Step-by-step explanation:
The solution to a system of equations given graphically is at the point of intersection of the 2 lines.
The lines intersect at (- 3, - 5 ) ← solution
