The second option, 7 rolls of quarters and 4 rolls of dimes.
7*10=70
4*5=20
70+20=90
2x16 is 32 so you would take square root of 16 out which is 4 and leave the 2 inside. So the answer is 4sqrt(2)
16 because 48/3 = 16 and we know that he started with 50 chocolates then distributed 3 times the number of friends present. This is written as 50 - 3x. We also know that there were 2 chocolates left so -3x = 2 - 50 which when simplified is x = 48/3 which equals 16.
Answer:
![3x^{2}y^{2}\sqrt[4]{7xy^{3}}](https://tex.z-dn.net/?f=3x%5E%7B2%7Dy%5E%7B2%7D%5Csqrt%5B4%5D%7B7xy%5E%7B3%7D%7D)
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Step-by-step explanation:
Since we have to find the simplified form of the expression as below
![\sqrt[4]{567x^{9}y^{11}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B567x%5E%7B9%7Dy%5E%7B11%7D%7D)
we will solve the expression as below
![=[567x^{9}y^{11}]^{\frac{1}{4}}](https://tex.z-dn.net/?f=%3D%5B567x%5E%7B9%7Dy%5E%7B11%7D%5D%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D)
![=3x^{2}y^{2}\sqrt[4]{7xy^{3}}](https://tex.z-dn.net/?f=%3D3x%5E%7B2%7Dy%5E%7B2%7D%5Csqrt%5B4%5D%7B7xy%5E%7B3%7D%7D)
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