Answer:
The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.
Step-by-step explanation:
This is a problem of optimization.
We have to minimize the time it takes for the lifeguard to reach the child.
The time can be calculated by dividing the distance by the speed for each section.
The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.
Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:
Then, the time (speed divided by distance) is:
To optimize this function we have to derive and equal to zero:
As , the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.
Answer:
5feet
Step-by-step explanation:
1 foot= 12 inches
1 inches = 1/12 feet
60 inches= 60x1/12= 5 feet
The answer to this is x/2 = 3.
4:5 because a quadrilateral has 4 sides and a pentagon has 5 sides
Form equation
y = mx + c
y = (rise/run).x + c
y = (11-1 / 3--2)x + c
y = 2x + c
11 = 2(3) + c
Find c (y-intercept)
11 - 6 = c
c = 5
Final equation of line
y = 2x + 5
Substitute given possible x-values in to find y-values
y = 2(1) + 5 = 7 (1,7)
y = 2(2) + 5 = 9 (2,9)
Therefore d is correct