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AlladinOne [14]
3 years ago
6

PLEASE HELP IN ONE MINUTE

Mathematics
1 answer:
marissa [1.9K]3 years ago
4 0

Answer:

no solution

Step-by-step explanation:

x2-x1/y2-y1

8-5/-4+4= 3/0

3/0 = N/0 solution

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What is the answer for number 5?
ad-work [718]

Answer:

2$ a pound

Step-by-step explanation:

I you look closely on the first point its (1,2)

x stands for pounds

y stands for dollars,

the slope is 2/1

(rise over run)

6 0
3 years ago
Read 2 more answers
Expand (2x -3y)^5 using the given formula.
horrorfan [7]
(2x-3y)^5

(2x-3y)(2x-3y)(2x-3y)(2x-3y)(2x-3y)

1st and 2nd power :
(2x-3y)(2x-3y) = 2x(2x-3y)-3y(2x-3y) = 4x² - 6xy - 6xy + 9y²
= 4x² - 12xy + 9y²

3rd power:
(2x-3y)(4x² - 12xy + 9y²) = 2x(4x² - 12xy + 9y²) - 3y(4x² - 12xy + 9y²)
8x³ - 24x²y + 18xy² - 12x²y +36xy² - 27y³
8x³ - 24x²y - 12x²y + 18xy² + 36xy² - 27y³
8x³ - 36x²y + 54xy² - 27y³

4th power
(2x-3y)(8x³ - 36x²y + 54xy² - 27y³) = 2x(8x³ - 36x²y + 54xy² - 27y³) -3y(8x³ - 36x²y + 54xy² - 27y³) = 16x^4 - 72x³y + 108x²y² - 54xy³ - 24x³y + 108x²y² - 162xy³ + 81y^4
16x^4 - 72x³y - 24x³y + 108x²y² + 108x²y² - 54xy³ - 162xy³ + 81y^4
16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4

5th power
(2x-3y)(<span>16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4)
2x(</span>16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4) - 3y(<span>16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4)
= 32x^5 - 192x^4y + 432x</span>³y² - 432x²y³ + 162xy^4 - 48x^4y + 288x³y² - 648x²y³ + 648xy^4 - 243y^5

32x^5 - 192x^4y -48x^4y + 432x³y² + 288x³y² - 432x²y³ - 648x²y³ + 162xy^4 + 648xy^4 - 243y^5

32x^5 - 240x^4y + 720x³y² - 1,080x²y³ + 810xy^4 - 243y^5
3 0
4 years ago
Is this graph linear or exponential
barxatty [35]
Its a graph linear i believe
3 0
3 years ago
Sandy had test scores of 20 25 17 22 and 21 (out of 25 total). what is her average (mean) score?
kolezko [41]
To find the mean you add up all the values and divide by how many there are.

So you would do:
20+25+17+22+21 = 105

Then divide:
105/5 (5 values) = 21

Her average score is 21 out of 25.

Hope this helps! :)
8 0
3 years ago
Square root of 512k^2. show work
kap26 [50]
We are asked to evaluate the square root of the expression  512 k^2.512 is not a perfect square but is divisible by the perfect square 256. square root of 256 is 16. hence square root of 512 is 16 square root of 2. square root of k2 meanwhile is equal to k. The answer hence is  16k square root of 2
7 0
3 years ago
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