Answer:
The proof is explained step-wise below :
Step-by-step explanation :
For better understanding of the solution see the attached figure :
Given : ABCD is a Parallelogram ⇒ AB ║ DC and AD ║ BC
Now, F lies on the extension of DC. So, AB ║ DF
To Prove : ΔABE is similar to ΔFCE
Proof :
Now, in ΔABE and ΔFCE
∠ABE = ∠FCE ( alternate angles are equal )
∠AEB = ∠FEC ( Vertically opposite angles )
So, by using AA postulate of similarity of triangles
ΔABE is similar to ΔFCE
Hence Proved.
Answer:
the top one would be my best he is because it has the two sybles in the problem they gave you
8z-8=6z+8
8x-6z=8+8
2z=16
Z=8
4pi/2pi = x/360
use a proportion
2 radians equals 360 degrees
x = 720 degrees
Answer:
C = -6
Step-by-step explanation:
1 +-7 =-6:::::::::::::::::::