1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vanyuwa [196]
2 years ago
14

The point c(-3,-2)is translated 1 unit left and 2 units up.what are the coordinates of the resulting point,c

Mathematics
1 answer:
yarga [219]2 years ago
7 0

translation makes this coordinate -4,0

You might be interested in
2. Which interval notation represents the set of all real
anygoal [31]
B. (2,20] is the correct answer
3 0
2 years ago
A portable CD player costs $48. How much is a payment of 25% of the cost
levacccp [35]

25% is the same is 1/4 of something. So you have to find what 1/4th of 48 is. To do that, just divide 48 by 4. and you get 12.

A 25% payment on a CD player that costs $48 would be $12. Hope that helps!

4 0
3 years ago
Factorise and divide 3^ 2 (2 ^2 − 14 + 24) ÷ 6 ( x − 4)​
Fiesta28 [93]

Answer:

i think its 21/x-4

Step-by-step explanation:

sorry if im wrong

3 0
2 years ago
Based on the number of voids, a ferrite slab is classified as either high, medium, or low. Historically, 5% of the slabs are cla
AnnyKZ [126]

Answer:

(a) Name: Multinomial distribution

Parameters: p_1 = 5\%   p_2 = 85\%   p_3 = 10\%  n = 20

(b) Range: \{(x,y,z)| x + y + z=20\}

(c) Name: Binomial distribution

Parameters: p_1 = 5\%      n = 20

(d)\ E(x) = 1   Var(x) = 0.95

(e)\ P(X = 1, Y = 17, Z = 3) = 0

(f)\ P(X \le 1, Y = 17, Z = 3) =0.07195

(g)\ P(X \le 1) = 0.7359

(h)\ E(Y) = 17

Step-by-step explanation:

Given

p_1 = 5\%

p_2 = 85\%

p_3 = 10\%

n = 20

X \to High Slabs

Y \to Medium Slabs

Z \to Low Slabs

Solving (a): Names and values of joint pdf of X, Y and Z

Given that:

X \to Number of voids considered as high slabs

Y \to Number of voids considered as medium slabs

Z \to Number of voids considered as low slabs

Since the variables are more than 2 (2 means binomial), then the name is multinomial distribution

The parameters are:

p_1 = 5\%   p_2 = 85\%   p_3 = 10\%  n = 20

And the mass function is:

f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z

Solving (b): The range of the joint pdf of X, Y and Z

Given that:

n = 20

The number of voids (x, y and z) cannot be negative and they must be integers; So:

x + y + z = n

x + y + z = 20

Hence, the range is:

\{(x,y,z)| x + y + z=20\}

Solving (c): Names and values of marginal pdf of X

We have the following parameters attributed to X:

p_1 = 5\% and n = 20

Hence, the name is: Binomial distribution

Solving (d): E(x) and Var(x)

In (c), we have:

p_1 = 5\% and n = 20

E(x) = p_1* n

E(x) = 5\% * 20

E(x) = 1

Var(x) = E(x) * (1 - p_1)

Var(x) = 1 * (1 - 5\%)

Var(x) = 1 * 0.95

Var(x) = 0.95

(e)\ P(X = 1, Y = 17, Z = 3)

In (b), we have: x + y + z = 20

However, the given values of x in this question implies that:

x + y + z = 1 + 17 + 3

x + y + z = 21

Hence:

P(X = 1, Y = 17, Z = 3) = 0

(f)\ P{X \le 1, Y = 17, Z = 3)

This question implies that:

P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) + P(X = 1, Y = 17, Z = 3)

Because

0, 1 \le 1 --- for x

In (e), we have:

P(X = 1, Y = 17, Z = 3) = 0

So:

P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) +0

P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)

In (a), we have:

f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z

So:

P(X=0; Y=17; Z = 3) = \frac{20!}{0! * 17! * 3!} * (5\%)^0 * (85\%)^{17} * (10\%)^{3}

P(X=0; Y=17; Z = 3) = \frac{20!}{1 * 17! * 3!} * 1 * (85\%)^{17} * (10\%)^{3}

P(X=0; Y=17; Z = 3) = \frac{20!}{17! * 3!} * (85\%)^{17} * (10\%)^{3}

Expand

P(X=0; Y=17; Z = 3) = \frac{20*19*18*17!}{17! * 3*2*1} * (85\%)^{17} * (10\%)^{3}

P(X=0; Y=17; Z = 3) = \frac{20*19*18}{6} * (85\%)^{17} * (10\%)^{3}

P(X=0; Y=17; Z = 3) = 20*19*3 * (85\%)^{17} * (10\%)^{3}

Using a calculator, we have:

P(X=0; Y=17; Z = 3) = 0.07195

So:

P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)

P(X \le 1, Y = 17, Z = 3) =0.07195

(g)\ P(X \le 1)

This implies that:

P(X \le 1) = P(X = 0) + P(X = 1)

In (c), we established that X is a binomial distribution with the following parameters:

p_1 = 5\%      n = 20

Such that:

P(X=x) = ^nC_x * p_1^x * (1 - p_1)^{n - x}

So:

P(X=0) = ^{20}C_0 * (5\%)^0 * (1 - 5\%)^{20 - 0}

P(X=0) = ^{20}C_0 * 1 * (1 - 5\%)^{20}

P(X=0) = 1 * 1 * (95\%)^{20}

P(X=0) = 0.3585

P(X=1) = ^{20}C_1 * (5\%)^1 * (1 - 5\%)^{20 - 1}

P(X=1) = 20 * (5\%)* (1 - 5\%)^{19}

P(X=1) = 0.3774

So:

P(X \le 1) = P(X = 0) + P(X = 1)

P(X \le 1) = 0.3585 + 0.3774

P(X \le 1) = 0.7359

(h)\ E(Y)

Y has the following parameters

p_2 = 85\%  and    n = 20

E(Y) = p_2 * n

E(Y) = 85\% * 20

E(Y) = 17

8 0
2 years ago
Solve for t.<br><br><br><br> 3/4t = 1/4<br><br><br><br> 1/3<br><br> 1<br> 4/3<br> 4
yawa3891 [41]
The correct answer would be t=1/3
4 0
3 years ago
Other questions:
  • PLEASE HELP!!!
    10·1 answer
  • A marble is drawn at random from a bag containing 2 blue marbles, 3 yellow marbles, and 7 orange marbles. What is the probabilit
    14·1 answer
  • When a survey was conducted among 100 students to find their favorite pizza topping, 45 students voted for pepperoni, 25 for mus
    7·1 answer
  • Sophie and Simon are peeling a pile of potatoes for lunch in the cafeteria. Sophie can peel all the potatoes by herself in 45 mi
    8·1 answer
  • 6.3.6. Among the early attempts to revisit the death postponement theory introduced in Case Study 6.3.2 was an examination of th
    7·1 answer
  • J(2x+9) m(6x-1)<br> i don’t get this at all
    8·1 answer
  • C -21= 41 <br><br><br>What is the solution for this equation?​
    12·2 answers
  • Answers and the top is to read it pls help for BIG BRAIN!
    6·2 answers
  • Help me I don't understand
    9·1 answer
  • Please help quiz do in 50 minutes show work​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!