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Alex73 [517]
3 years ago
14

Sarah makes and sells pottery bowls. She has costs totaling $10,000 per year plus a cost of $7 for each bowl she makes. If she s

ells the bowls for $25 each, what is the minimum number she must sell each year to earn at least $25,000 profit?
Mathematics
2 answers:
zhenek [66]3 years ago
8 0
X = # of bowls
25x - (10,000 + 7x) ≥ 25,000
25x - 10,000 - 7x ≥ 25,000
18x ≥ 35,000
x ≥  4,375 bowls

To make a minimum of a $25,000 profit, Sarah has to make at least 4,375 bowls every year.
GenaCL600 [577]3 years ago
5 0
She needs to sell at least 1,400 pottery bowls in order to get a $25,000 profit.
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Answer:

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cosine and sec are inverse of each other.

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Step-by-step explanation:

Given point on terminal side of an angle (\frac{1}{3},\frac{1}4).

Kindly refer to the attached image for the diagram of the given point.

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Point B will be (\frac{1}{3},0)

Now, let us consider the right angled triangle \triangle OBA:

Sides:

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Using Pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow OA^{2} = OB^{2} + AB^{2}\\\Rightarrow OA^{2} = \frac{1}{3}^{2} + \frac{1}{4}^{2}\\\Rightarrow OA = \sqrt{\frac{1}{3}^{2} + \frac{1}{4}^{2}}\\\Rightarrow OA = \sqrt{\frac{4^2+3^2}{3^{2}.4^2 }}\\\Rightarrow OA = \frac{5}{12}

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cos\angle AOB = \dfrac{Base}{Hypotenuse}

\Rightarrow cos \angle AOB = \dfrac{\frac{1}{3}}{\frac{5}{12}}\\\Rightarrow cos\angle AOB = \dfrac{4}{5}

tan\angle AOB = \dfrac{Perpendicular}{Base}

\Rightarrow tan\angle AOB = \dfrac{3}{4}

cosec \angle AOB = \dfrac{Hypotenuse}{Perpendicular}

\Rightarrow cosec\angle AOB = \dfrac{5}{3}

sec\angle AOB = \dfrac{Hypotenuse}{Base}

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Answer:

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