P = f*s
f +3s = 60
p = (60 -3s)*s = 3(20 -s)*s
This equation describes a parabola that opens downward. The roots of the equation are s=0 and s=20, so the axis of symmetry is s=(0+20)/2 = 10. That is, the vertex (maximum) will be found at s=10.
The second number is 10. The first number is 60-3*10 = 30.
The product is maximized when the first number is 30 and the second is 10.
Use the sine theorem:
sin(angle A) / length of side a = sin (angle B) / lenght of side b
Here:
angle A = 32°
length of side a = length from school to library = x
angle B = 110°
length of side b = 2.2 mi
Then, sin(32°) / x = sin(110°) / 2.2 mi
=> x = 2.2 mi * sin (32) / sin (110)
x = 1.24 mi
Therefore the answer is the option B. 1.2 mi
So first fin the area then surface area and the volume
volume=legnth times width times heigh ttimes width=3 times 5 times 6=90
volume=90
surface area=(2 times 3 times 5)+(2 times 3 times 6)+(2 times 5 times 6)=(2 times 15)+(2 times 18)+(2 times 30)=30+36+60=126
volume=90
surface area=126
radio fo surface area to volume
90:126
simplify and treat as fraction
5:7
since they area all decimals they expect us to divide
5/7=.714
the closest answer is D, 0.7
the answer is D 0.7
The floor of the school has the shape of triangle.
So, the area of the floor is equal to the area of that triangle with base = 26 in, and height = 33 in.
The area of triangle = 0.5 * base * height
= 0.5 * 26 * 33 = 429 in²
∴ The area of the floor = 429 in²
Answer:
The answer is 1,787.75 square inches
Step-by-step explanation:
