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3 years ago

Which of the following is a hazardous risk associated with excavations?

Advanced Placement (AP)

2 answers:

Arada [10]3 years ago

7 0

I would have to say A. All answer choices are hazardous risks

Agata [3.3K]3 years ago

4 0

Excavations refer to the practice of digging up land to uncover something – generally it is used for archaeological purposes. During excavations, there are numerous potential for an accident to occur because of the dangerous environment.

From all the options mentioned, asphyxiation due to oxygen, fire, and inhalation of toxic fumes are all liable to occur, thus making (A) all answer choices are hazardous risks the best option to answer the question.

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I think it’s 0100101101

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3 years ago

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Scientists use models of the Sun to better understand how it works. The currently accepted model of the Sun indicates that it ha

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energy is radiated out from the core, then, carried to the outer layers by convection.

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2 years ago

Ms. England is planning a party for students who have met their goal of reading seven books during the most recent nine weeks of

Gennadij [26K]

Answer:

Ms. England should buy 8 pizzas and 32 drinks.

Explanation:

Let p = the number of pizzas and d = the number of drinks. Each pizza costs $12 so the cost of all of the pizzas is ($12)*p. Each drink costs $0.50, so the cost of all of the drinks is ($0.50)*d. The total cost, then, is:

Total Cost = Cost of Pizzas + Cost of Drinks

$112 = ($12)p + (($0.50)*d

Now you buy 4 times as many drink as pizzas, so:

Number of Drinks = 4 * (Number of Pizzas)

d = 4*p

Now lets' substitute 4p in place of d in the total cost equation and solve for p:

$112 = ($12)p + ($0.50)*d

$112 = ($12)p + ($0.50)*(4p) [Substituted 4p in place of d]

112 = 12p + 2p

112 = 14p

Solve for p, the number of pizzas. Once you have p, the number of drinks is d = 4*p.

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3 years ago

9*B

jonny [76]

Answer:

a. The bug is moving at a constant speed of -2 m/s

b. The total distance traveled by the bug is 17 meters

c. The distance the bug end up from its starting point is 3 meters

d. i. The bugs velocity is 0 when t = 0, 5, or 10 seconds,

ii. The bugs velocity is > 0 at 5 ≤ t ≤ 10

iii. The bugs velocity is < 0 at 0 ≤ t ≤ 5

e. i. The bug's acceleration is 0 at 2 ≤ t ≤ 4

ii. The bug's acceleration is > 0 at 4 ≤ t ≤ 6 and 8 ≤ t ≤ 9

iii. The bug's acceleration is > 0 at 0 ≤ t ≤ 2 and 9 ≤ t ≤ 10

f. The time the bug passes the starting point is approximately 8.83 seconds

Explanation:

a. When 2 ≤ t ≤ 4, the bug is moving at a constant speed of -2 m/s

b. The total distance the bug traveled is given by the area under the velocity-time graph which consist of two trapezoid and a triangle and is therefore is given as follows;

The area of the first (negative) trapezoid = -2 × (2 + 5)/2 = -7

The area of the second trapezoid = 2 × (3.5 + 5)/2 = 8.5

The area of the triangle = 1/2 × 1.5 × 2 = 1.5

The sum of the magnitude of the areas = The total distance traveled by the bug = $\left | -7 \right |$ + 8.5 + 1.5 = 17

The total distance traveled by the bug = 17 meters

c. The distance the bug end up from its starting point is given by the sum of the displacement (total displacement) of the bug

The total displacement of the bug = -7 + 8.5 + 1.5 = 3

The distance the bug end up from its starting point = The total displacement of the bug = 3 meters

d. i. The bugs velocity is 0 when the graph crosses the time, 't', axis, which is at points for time, t = 0 seconds, t = 5 seconds, and t = 10 seconds

ii. The bugs velocity is > 0 between the times, 5 ≤ t ≤ 10

iii. The bugs velocity is < 0 between the times, 0 ≤ t ≤ 5

e. i. The bug's acceleration is 0 between the times, 2 ≤ t ≤ 4

ii. The bug's acceleration is > 0 between the times, 4 ≤ t ≤ 6 and 8 ≤ t ≤ 9

iii. The bug's acceleration is > 0 between the times, 0 ≤ t ≤ 2 and 9 ≤ t ≤ 10

f. The bug passes the starting point at the time, 8 + t, where 't', is given by the area of a trapezoid as follows;

2 = t × (2 + 2 + t)/2

∴ 4 = 4·t + t²

t² + 4·t - 4 = 0

(t + (2 + 2·√2))·(t - (2·√2 - 2))

∴ t = 2·√2 - 2

The time the bug passes the starting point = 8 + 2·√2 - 2 = 6 + 2·√2 ≈ 8.83

The time the bug passes the starting point ≈ 8.83 seconds

4 0

2 years ago

What should you complete to be eligible for the Federal Work-Study Program?

MrRa [10]

Answer:

FAFSA

Explanation:

A P E X

8 0

3 years ago

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