All categories

2 years ago

You have 32 grams of a radioactive kind of gold. If its half-life is 3 days, how much will be left after 6 days?

Mathematics

2 answers:

Digiron [165]2 years ago

6 0

D. 8 grams
The equation
Ending Amount = Beginning Amount / 2(time / half-life)
32/2^(6/3)
32/2^2
32/4
=8

Fiesta28 [93]2 years ago

4 0

Answer:

d. 8 grams.

Step-by-step explanation:

After 1 half life there is 1/2 * 32 = 16 grams left , after another half-life ( at 6 days) there is 1/2 * 16 = 8 grams left.

You might be interested in

Kristl has saved 30%

Tom [10]

Answer:

$180

Step-by-step explanation:

4 0

2 years ago

Nora drew a scale drawing of the middle school. The scale she use was 1 inch: 7 feet. The gym is 17 inches in the drawing. How i

emmainna [20.7K]

Answer: 119

Step-by-step explanation: if it’s 1:7,

then you’d have to do 17x7

5 0

2 years ago

Find x. Give your answer in the

ASHA 777 [7]

Answer:

Es in simplo deviso con lado

5 0

1 year ago

Graph f(x) =-2x^+16x-30 by factoring to find the solutions, then find the coordinates of the vertex, and the axis of symmetry. I

fredd [130]

Answer:

Observe attached image

Function zeros:

(3, 0), (5, 0)

Vertex:

(4, 2)

Axis of symmetry:

 $x =4$ 

Step-by-step explanation:

First factorize the function

$f (x) = -2x ^ 2 + 16x-30$

Take -2 as a common factor.

$-2(x ^ 2 -8x +15)$

Now factor the expression $x ^ 2 -8x +15$

You must find two numbers that when you add them, obtain the result -8 and multiplying those numbers results in 15.

These numbers are -5 and -3

Then we can factor the expression in the following way:

$f (x) = -2(x-5)(x-3)$

The quadratic function cuts the x-axis at x = 3 and at x = 5.

Now we find the coordinates of the vertex.

For a function of the form $ax ^ 2 + bx + c$ the x coordinate of its vertex is:

$x = \frac{-b}{2a}$

In the function $f (x) = -2x ^ 2 + 16x-30$

$a = -2\\b = 16\\c = 30$

Then the vertice is:

$x = \frac{-16}{2(-2)}\\\\x = 4$

The y coordinate of the symmetry axis is

$y = f (4) = -2 (4) ^ 2 +16 (4) -30\\\\y = 2$

The axis of symmetry is a vertical line that cuts the parabola in two equal halves. This axis of symmetry always passes through the vertex.

Then the axis of symmetry is the line

$x = 4$

The solutions and the vertice written as ordered pairs are:

Function zeros:

(3, 0), (5, 0)

Vertex:

(4, 2)

6 0

2 years ago

Can someone help?..........

kari74 [83]

The answer is number 1

6 0

2 years ago