What ? Don't make since bro
Answer:
Option C) 113.0 feet squared
Step-by-step explanation:
We are given the following in the question:
Radius of circular garden = 4 feet
Length of path around garden = 2 feet
We have to find the total area of garden and path.
The garden and path together makes a bigger circle with radius

Area of garden and path =

Putting values, we get,

Thus, the correct answer is
Option C) 113.0 feet squared
Answer:
15393.8cm sorry if im wrong
Answer:
d =(m-q)/a
Step-by-step explanation:

Recall that

where
is the angle between the vectors
whose magnitudes are
, respectively.
We have

