Answer:
result = 0
i = lo
while i <= hi:
result = result + i
i += 1
Explanation:
Initialize the <em>result</em> as 0 to hold the summation value.
Since we are asked not to change the value of <em>lo</em> and <em>hi</em>, our loop control variable is <em>i</em> and initially it starts from <em>lo.</em>
Since we are asked to add the number from <em>lo</em> to <em>hi, </em>while loop condition checks it.
While the condition satisfies (during each iteration), the value of <em>i</em> is added to the result and the value of <em>i</em> is incremented by one.
Answer:
i think its b
Explanation:
i did the test and got it right
The <DEL> or <Delete> key makes the first character AFTER the cursor
disappear, and everything after it then moves back one space to close up
the hole.
Example:
If I have this in my document ... Most trees are green.
And my cursor is after the 'a', like this: Most trees a|re green.
Now, if I hit the <delete> key, it deletes the
'r' after the cursor, and the hole closes up,
and the cursor stays where it is: Most trees a|e green.
Answer:
Total Memory= 4 KB = 4096 bytes = 32768 bits
Explanation:
<em><u>1. Data lines are 8 From D0 to D7</u></em>
so
Total memory at single address locations is 8 bits.
<em><u>2. Address lines are 12 (A0 to A11)</u></em>
There are 12 address lines but 3 out 12 are for selction of chip or memory bank.
so only 9 pins are there to address the locations on one chip.
Total No. of address locations on single chip = 2^9 = 512 locations
as 1 location is 1 byte so total memory of single chip is 512 bytes.
<u><em>3. Total Memory Bank </em></u>
There are total 3 selection pins for memory bank.
so
Total chips = 2^3 = 8.
<em><u>4. Total Memory </u></em>
Total size of 1 chip = 512 bytes
Total size of 8 chip = 8x512 bytes = 4096 bytes = 4096/1024 kb = 4 kb
<em>So total memory of system is 4 Kb = 4096 bytes = 32768 bits</em>
