First we take the first equation y=x2 - 2x +4 and substitute it for the value of y in the second equation...giving us, 8X + (x^2 - 2x +4) = 20 8x + x^2 - 2x +4 = 20 combine like terms x^2 + 6x + 4 = 20 subtract 20 fm both sides x^2 + 6x - 16 = 0 factor (x + 8) (x - 2) = 0 set both factors to = 0 x + 8 = 0 x - 2 = 0 solve x = -8 and 2 put these amounts into the regular equation to get the value of y leaving the correct answer as C.
