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NikAS [45]
3 years ago
14

Two large and 1 small pumps can fill a swimming pool in 4 hours. One large and 3 small pumps can also fill the same swimming poo

l in 4 hours. How many hours will it take 4 large and 4 small pumps to fill the swimming pool.(We assume that all large pumps are similar and all small pumps are also similar.)
if u get this right i will mark brainliest
Mathematics
1 answer:
kolezko [41]3 years ago
6 0

Let <em>x</em> and <em>y</em> be the unit rates at which one large pump and one small pump works, respectively.

Two large/one small operate at a unit rate of

(1 pool)/(4 hours) = 0.25 pool/hour

so that

2<em>x</em> + <em>y</em> = 0.25

One large/three small operate at the same rate,

(1 pool)/(4 hours) = 0.25 pool/hour

<em>x</em> + 3<em>y</em> = 0.25

Solve for <em>x</em> and <em>y</em>. We have

<em>y</em> = 0.25 - 2<em>x</em>   ==>   <em>x</em> + 3 (0.25 - 2<em>x</em>) = 0.25

==>   <em>x</em> + 0.75 - 6<em>x</em> = 0.25

==>   5<em>x</em> = 0.5

==>   <em>x</em> = 0.1

==>   <em>y</em> = 0.25 - 2 (0.1) = 0.25 - 0.2 = 0.05

In other words, one large pump alone can fill a 1/10 of a pool in one hour, while one small pump alone can fill 1/20 of a pool in one hour.

Now, if you have four each of the large and small pumps, they will work at a rate of

4<em>x</em> + 4<em>y</em> = 4 (0.1) + 4 (0.05) = 0.6

meaning they can fill 3/5 of a pool in one hour. If it takes time <em>t</em> to fill one pool, we have

(3/5 pool/hour) (<em>t</em> hours) = 1 pool

==>   <em>t</em> = (1 pool) / (3/5 pool/hour) = 5/3 hours

So it would take 5/3 hours, or 100 minutes, for this arrangement of pumps to fill one pool.

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21 Years Ago

Step-by-step explanation:

61 - 21 = 40

31 - 21 = 10

40/10 = 4

4 0
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Write the equation of a line that is perpendicular to -2/7x+9 that passes through the point (4, -6)
Anna11 [10]

Answer:

7y + 2x + 34 = 0

Step-by-step explanation:

The gradient for perpendicular, m = -2/7

The formular equation, y - y1 = m(x - x1)

The equation of line through (4, -6) is:

y - (-6) = -2/7(x - 4)

y + 6 = -2x/7 + 8/7

7y + 42 + 2x - 8 = 0

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6 0
3 years ago
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The radioactive isotope radium has a half-life of 1,600 years. The mass of a 100-gram sample of radium will be______ grams after
Olenka [21]
To solve this we are going to use the half life equation N(t)=N_{0} e^{( \frac{-0.693t}{t _{1/2} }) }
Where:
N_{0} is the initial sample
t is the time in years
t_{1/2} is the half life of the substance
N(t) is the remainder quantity after t years 

From the problem we know that:
N_{0} =100
t=200
t_{1/2} =1600

Lets replace those values in our equation to find N(t):
N(200) =100e^{( \frac{(-0.693)(200)}{1600}) }
N(200)=100e^{( \frac{-138.6}{1600} )}
N(200)=100e^{-0.086625}
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We can conclude that after 1600 years of radioactive decay, the mass of the 100-gram sample will be 91.7 grams.

8 0
3 years ago
One pound of swordfish costs as much as 1.5 pounds of salmon. Mrs. O pays $39 for 2 pounds of salmon and 3 pounds of swordfish.
Dimas [21]

Answer:

The ratio of the amount for swordfish to the amount of salmon is 6:4

Step-by-step explanation:

Given as :

The price for 1 pound of swordfish = The price of 1.5 pound of salmon

So, On this relation

The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 )  pound of salmon

i.e The price for 2 pound of swordfish = The price of 3 pound of salmon

Now According to question

Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39

Let the money she pay for swordfish = 2 sw

And The money she pay for salmon = 3 sa

∵, The total money she pay for both  = $ 39

I.e  2 sw + 3 sa = 39

As 2 sw = 3 sa

So, 3 sa + 3 sa = 39

Or, 6 sa = 39

or, sa = \frac{39}{6} = \frac{13}{2}

∴ sw = \frac{13}{2} × \frac{3}{2}

or, sw = \frac{39}{4}

Now, the ratio of the amount for swordfish to the amount of salmon = \frac{\frac{39}{4}}{\frac{13}{2}}

I.e The ratio = \frac{6}{4}

Hence The ratio of the amount for swordfish to the amount of salmon is 6:4

Answer

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3 years ago
What is the surface area of this right rectangular prism glass slab with dimensions of 20 inches by 3 inches by 12 inches?
Art [367]

Answer:

C. 672

Step-by-step explanation:

7 0
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