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mylen [45]
3 years ago
8

!!!!PLEASE HELP!!!! Tracy deposited $59 into a bank account that earned 3.5% simple interest each year. If no money was deposite

d into or withdrawn from the account, how much money was in the account after ​ 112112 ​ years? Round your answer to the nearest cent.
Mathematics
1 answer:
oksian1 [2.3K]3 years ago
8 0

If you meant “112” years the answer is $6,839.28, if you actually meant 112112 the answer is $6,846,119.28

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Answer:

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Match each equation with its solution set. Tiles a2 − 9a + 14 = 0 a2 + 9a + 14 = 0 a2 + 3a − 10 = 0 a2 + 5a − 14 = 0 a2 − 5a − 1
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We have that

N 1)
a²<span> − 9a + 14 = 0 
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Rewrite as perfect squares

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the solution problem N 1 is the pair {7, 2}


N 2) 

a²<span> + 9a + 14 = 0
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Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² +9a+20.25)=-14+20.25

Rewrite as perfect squares

(a+4.5)²=6.25--------> (a+4.5)=(+/-)√6.25

a1=-4.5+√6.25-----> a1=-2

a2=-4.5-√6.25-----> a2=-7

the solution problem N 2 is the pair {-2,-7}

N 3) 

a² + 3a − 10 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 3a)=10

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 3a+2.25)=10+2.25

Rewrite as perfect squares

(a+1.5)²=12.25------> (a+1.5)=(+/-)√12.25

a1=-1.5+√12.25-----> a1=2

a2=-1.5-√12.25-----> a2=-5

the solution problem N 3 is the pair {2, -5}


N 4)

a²<span> + 5a − 14 = 0
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Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 5a) =14

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Rewrite as perfect squares

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a1=-2.5+√20.25-----> a1=2

a2=-2.5-√20.25-----> a2=-7

the solution problem N 4 is the pair {2, -7}


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Group terms that contain the same variable, and move the constant to the opposite side of the equation

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