Question

Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as 7 centimeters. The hypotenuse is labeled as 13 centimeters.Jayden's WorkSheridan's Worka2 + b2 = c2a2 + b2 = c272 + 132 = c272 + b2 = 13249 + 169 = c249 + b2 = 169218 = c2b2 = 120Square root 218 equals square root c squared.Square root b squared equals square root 120.14.76 ≈ cb ≈ 10.95Is either of them correct? Explain your reasoning

Answer 1

Answer:

can you explain why sheridan is right? like in words.

Step-by-step explanation:

PLEASEEEE

Answer 2

Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

The lengths side of a right triangle must satisfy the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

where

a and b are the legs

c is the hypotenuse (the greater side)

In this problem

Let

$a=7\ cm\\c=13\ cm$

substitute

$13^{2}=7^{2}+b^{2}$

Solve for b

$169=49+b^{2}$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

we have that

Jayden's Work

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\b=13\ cm$

substitute and solve for c

$7^{2}+13^{2}=c^{2}$

$49+169=c^{2}$

$218=c^{2}$

$c=\sqrt{218}\ cm$

$c=14.76\ cm$

Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

Sheridan's Work

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\c=13\ cm$

substitute

$7^{2}+b^{2}=13^{2}$

Solve for b

$49+b^{2}=169$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

therefore

Sheridan's Work is correct