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kkurt [141]
3 years ago
12

What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0? Use u substitution and the quadratic formula to solve

Mathematics
1 answer:
professor190 [17]3 years ago
8 0

Answer:

x=−41/20

Step-by-step explanation:

(2x+3)(2)+8(2x+3)+11=0

Step 1: Simplify both sides of the equation.

(2x+3)(2)+8(2x+3)+11=0

(2x)(2)+(3)(2)+(8)(2x)+(8)(3)+11=0(Distribute)

4x+6+16x+24+11=0

(4x+16x)+(6+24+11)=0(Combine Like Terms)

20x+41=0

20x+41=0

Step 2: Subtract 41 from both sides.

20x+41−41=0−41

20x=−41

Step 3: Divide both sides by 20.

20x/20=−41/20

x=−41/20

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Write 10 1/2 as a decimal number
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Answer:

10.5

Step-by-step explanation:

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43/645= I need the to show the work
Licemer1 [7]
I'm guessing you need 43/645 simplified:

First, we need to find the greatest common factor (GCF) of the numerator (43) and the denominator (645). To do so, we list all the factors of each number and find the common ones.

Factors of 43: 1, 43
Factors of 645: 1, 3, 5, 15, 43, 129, 215, 645

Out of the listed factors for each number, which numbers are common between the two? The common factors are 1 and 43. Since we are looking for the GREATEST common factor, which number out of 1 and 43 is the greatest? The GCF is 43.

Second, we can now divide the numerator (43) and the denominator (645) by the GCF we recently found which was 43. 

43 \div 43 = 1 \\ 645 \div 43 = 15

Third, our new simplified fraction is 1/15. We collected our new numerator and denominator.

Answer in fraction form: \fbox {1/15}
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The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
zloy xaker [14]

Answer:

103=  p small

plarge = 123

Step-by-step explanation:

We know that the the ratio of the areas is the scale factor squared/

Larger triangle over smaller triangle

72

----- = scale factor ^2

50

simplify by dividing by 2 on top and bottom

36

----- = scale factor ^2

25

Take the square root of each side

sqrt(36)

-------------- = sqrt(scale factor ^2)

sqrt(25)

6

-------------- = scale factor

5

The ratio of the perimeters is the scale factor

p large             6

-------------- = ----------------

 p small                5

Using cross products

6 p large = 5 p small

We know the sum is 226

p large + p small = 226

p large = 226 - p small

We have 2 equation and 2 unknowns

6 p large = 5 p small

Substitute for p large

6 (226 - p small) = 5 p small

1356 - 6 p small = 5 p small

Add 6 p small to each side

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divide by 11

1356/11 =  p small

P large = 226-1356/11

p large = 2486/11-1356/11

plarge = 1130/11

The solution requires whole number answers so

1356/11 =  p small

123.27 which rounds to 123

plarge = 1130/11

plarge = 102.7272 = 103

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