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katovenus [111]
3 years ago
8

Using a straightedge draw a random triangle now carefully cut it out next amputate the angles by snipping through adjacents side

s now move the angles together so the vertices all touch

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
4 0
This is usually used as a proof that triangles have 180°.  Look at the attached figures.  If you cut off angle A, angle B and angle C and rotate them so that their vertices touch, you form a half-circle out of them (or a straight line).  We know that half a circle is 1/2 of 360° or 180; therefore all 3 angles in a triangle must add up to 180°.

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The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

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For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

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$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

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Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$, and

$x=8-\sqrt{10}$.

To learn more about quadratic equations refer to:

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