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crimeas [40]
2 years ago
7

Find a number x such that g(x) = -4

Mathematics
1 answer:
mel-nik [20]2 years ago
3 0

Answer:

C: x = 7

Step-by-step explanation:

The easiest way to do this is to simply try all of the x-vales given as options.

Option 1: x = -1

Since -1 \leq 0, we'll use the first equation.

g(x)=\mid x \mid - 2\\g(-1)=\mid -1 \mid - 2 = 1 - 2 = -1

As we can see, g(-1) is not -4.

Option 2: x = 3

Since 0 < 3 < 4, we'll use the 2nd equation.

g(x) = x-3\\g(3) = 3-3 = 0

Not -4.

Option 3: x = 7

Since 4 \leq 7, we'll use the 3rd equation.

g(x) = 3-x\\g(7) = 3-7 = -4

Tada! We have found a number such that g(x) = -4, it is 7. Since we only need to find a number, not all numbers, we don't have to check the last option. However, if you're curious:

Option 4: x = 4

Since 4 \leq 4 (less than <em>or equal to</em>), we'll use the 3rd equation.

g(x) = 3-x\\g(4) = 3-4 = -1

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Allushta [10]

Answer:

B. 165

Step-by-step explanation:

Let w represent the number of weeks.

We have been given that a wrestler currently weighs 189 pounds and is losing 0.5 of a pound per week. So the weight lost by wrestler in w weeks would be 0.5w.

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4 0
3 years ago
Halle la ecuación del eje x y la ecuación del eje y, usando dos puntos que se encuentren sobre los mismos.
lisov135 [29]

Una linea recta ( cualquier eje coordenado es una línea recta) queda definida si se conocen dos puntos que están sobre ella.

Solución:

Ecuación del eje x      y = 0

Ecuación del eje y      x = 0

Para darle respuesta a la pregunta podemos seguir el siguiente procedimiento:

  • Escogemos dos puntos arbitrarios sobre el eje x, por ejemplo

P ( 2 ; 0 )  y Q ( 5 ; 0 )         ( todos los puntos sobre el eje x tienen coordenada y = 0.

Según la cual  m = (y₂ - y₁)/ ( x₂ - x₁ )    m = 0

  • Usamos la ecuación pendiente-Intercepto

y = m×x + b         donde m es la pendiente y b el intercepto con el eje y

y entonces tenemos:

  • m = 0    b ( 0 ; 0 )
  • Por sustitución en la ecuación pendiente-intercepto

y = 0

Procediendo de forma similar obtendremos la ecuación del eje y

P´( 0 ; 4 )     Q´( 0 : 8 ) entonces

y = m×x + b

En este caso, la pendiente no es definida ( tang 90° ) y b es de nuevo el punto b ( 0 ; 0).

A partir de  que todos y cada uno de los puntos sobre el eje y son  de valor 0 para x, concluímos que  ecuación del eje y es

x = 0

Enlaces de interés:brainly.com/question/21135669?

8 0
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