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Sidana [21]
3 years ago
13

1 & 4 please help me

Mathematics
1 answer:
Setler [38]3 years ago
8 0
Kyle has just finished playing his 6th game of the season (but there will be additional games to play before the season is over).  He scores 4 points in this 6th game, bringing his per-game average down to 9 points.  We need to write a formula for this average:

sum of all points scored by Kyle       a+b+c+d+e+4
------------------------------------------- = -------------------------  = 9 points per game
                 6 games                                     6 games

This could also be written as a+b+c+d+e+4=(9 points/game)(6 games), or

a+b+c+d+e+4 = 54 points, or a+b+c+d+e = 50 points.

Now we have to think about the median.  Since n (the number of scores) is an even number, we find the median of these scores as follows:

1) arrange the scores in ascending order (we always do this when finding a median score)
2) take the two middle scores, add them together and divide by 2, to determine the median score

I am posting this discussion now to ensure we don't lose it (since my Internet connection has not been dependable).
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In a lab experiment, the decay of a radioactive isotope is being observed. On the first day of the experiment the mass of the su
strojnjashka [21]

The recursive formula is mathematically given as

a_n=1266.77e^n

<h3>What is the recursive formula?</h3>

Generally, the equation for the decay is  mathematically given as

at=a_oe^{-\lambda t}

Hence

a1=1400e^{-0.1 (1)}

In conclusion,

a_n=1400e^{-0.1 (n)}\\\\a_n=1266.77e^n

Read more about recursive formula

brainly.com/question/8972906

#SPJ1

7 0
2 years ago
How many integers between 2020 and 2400 have four distinct digits arranged in increasing order?
malfutka [58]

Answer:  E=15

There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Step-by-step explanation:

This can be obtained by after a simple counting of number from 2020 and 2400 as follows:

The first set of integers are:

2345, 2346, 2347, 2348, and 2349.

Therefore, there are 6 integers in first set.

The second set of integers are:

2356, 2357, 2358, and 2359.

Therefore, there are 4 integers in second set.

The third set of integers are:

2367, 2368, and 2369.

Therefore, there are 3 integers in third set.

The fourth set of integers are:

2378, and 2379.

Therefore, there are 2 integers in fourth set.

The fifth and the last set of integer is:

2389

Therefore, there is only 1 integers in fifth set.

Adding all the integers from each of the set above, we have:

Total number of integers = 6 + 4 + 3 + 2 + 1 = 15

Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Sorry if it is incorrect

8 0
3 years ago
Read 2 more answers
Mixed fractions help please
matrenka [14]

The answer is 15 2/5


8 0
3 years ago
How do I do question 2 &amp; 3 ? Please help thank you
zepelin [54]
<h2>2.</h2><h3>Given</h3>
  • y=2x(2 -3x)
<h3>Find</h3>
  • y·y'' +x·y' -16 in simplest form
<h3>Solution</h3>

It is convenient to expand the expression for y to ease determination of derivatives.

... y = 4x -6x²

... y' = 4 -12x

... y'' = -12

Then the differential expression can be written as

... (4x -6x²)(-12) +x(4 -12x) -16

... = -48x +72x² +4x -12x² -16

... = 60x² -44x -16

<h2>3.</h2><h3>Given</h3>
  • y = 16/x +x³/3
<h3>Find</h3>
  • the turning points
  • the extreme(s)
<h3>Solution</h3>

The derivative is

... y' = -16x^-2 + x^2

This is zero at the turning points, so

... -16/x^2 +x^2 = 0

... x^4 = 16 . . . . . . . . . multiply by x^2, add 16

... x^2 = ±√16 = ±4

We're only interested in the real values of x, so

... x = ±√4 = ±2 . . . . . . . x-values at the turning points

Then the turning points are

... y = 16/-2 +(-2)³/3 = -8 +-8/3 = -32/3 . . . . for x = -2

... y = 16/2 + 2³/3 = 8 +8/3 = 32/3 . . . . . . . for x = 2

The maximum is (-2, -10 2/3); the minimum is (2, 10 2/3).

3 0
4 years ago
Question 1
Alex777 [14]
Riki ...
Most questions on Brainly offer 5 points in return for answering one question,
but here you've listed five of them to be answered for 5 points.  That's kind of
much.
Also, it's not clear what cylinders Question-2 and Questioin-3 refer to. 
They might be the two pictures under the question, but we don't rally know.
Fortunately, all five of your questions are answered with the same formula ...
the formula for the volume of a cylinder.
Here it is:

         Volume of a cylinder = ( π ) · (radius)² · (height or length)  .

                                       V  =  π  R²  H  .

That's it.  That's all you need to answer any or all of the five questions.
So I've actually given you everything you need to answer them, and in
doing that, I've already earned 5 points.  But, being the ever helpful guy
that I am, I'll work out two of the questions for you, to show you how to
use the formula.

Question #1).  <span>A cylinder has a radius of 14 m and a height of 6 m.

              </span>Volume  =  π  R²  H 

                           =  (π)  (14m)²  (6m)

                           =  (π)  (196m²)  (6m)

                           =      1,176 π  m³  =  71,763,930 π in³

(Notice how confusingly and sloppily the question is written . . .
the dimensions of the cylinder are given in meters, but the
answer choices are listed in cubic-inches.  I've shown the
answer in both units.)

Question 5).  <span>A can has a radius of 2.8 feet and holds 86.21 cubic feet.

           </span><span>Volume  =  π  R²  H

           86.2 ft³  =  π (2.8 ft)² (Height)

            86.2 ft³  =  π (7.84 ft²) (Height)

           Height  =  (86.2 ft³) / (7.84 π ft²)

                        =         3.5 ft

</span>
5 0
3 years ago
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