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Bond [772]
3 years ago
10

During ur last shift, 20 babies were born. 10 had blue eyes, and 10 had brown eyes

Biology
2 answers:
Nady [450]3 years ago
5 0
Each person then has 4 total alleles that determine their eye color. The B allele (brown) is always dominant. The blue eye trait is always recessive.
diamong [38]3 years ago
5 0

Answer:

Possible genotypes and their frequencies

Frequency of babies with blues eye having genotype "bb" is 0.5

Frequency of babies with brown eye having genotype "Bb" is 0.41

Frequency of babies with brown eye having genotype "BB" is 0.084

Explanation:

In a normal human being, brown eye color is dominant over blue eye color.

Thus B is dominant over b

Now,

Babies with blue eye colour will have genotype "bb" because it is a recessive trait thus both the alleles must be the recessive allele.

Therefore,

q^{2} = \frac{10}{20} \\=0.5

Thus

q=\sqrt{0.5} \\= 0.707\\=0.71

While the genotype of brown babies can be either homozygous dominant or heterzygous dominant

Now as per Hardy Weinberg's equation -

p+q=1

so p=1-0.71

p = 0.29

Thus frequency of babies with genotype "BB" is equal to p^{2}

= 0.084

Now frequency of babies with genotype "Bb" is

1-p^{2} -q^{2} =2pq

2pq = 0.41

Thus,

Frequency of babies with blues eye having genotype "bb" is 0.5

Frequency of babies with brown eye having genotype "Bb" is 0.41

Frequency of babies with brown eye having genotype "BB" is 0.084

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