Answer:
A) 17 m B) 20.8 m
Step-by-step explanation:
I cannot mark on the image but you can find the length of A to the bottom of the shape by subtracting 26-11
26-11 = 15
I will label the triangle as ABC (AB the length we trying to find, BC is 15 *it is angle B to the intercept of A and the bottom of the shape, AC is 8 because it is parallel to the given length 8)
AB is the hypotenuse
We can use the pythagorean theorem to find length AB (a^2 + b^2 = c^2)
a and b is the legs which is 8 and 15
8^2 + 15^2 = AB^2
64 + 225 = AB^2
289 = AB^2
√289 = AB (to undo a square, you use square roots)
√289 = 17
AB = 17 m
Now we need to find the hypotenuse of AC
the same thing, we did for problem A, use the pythagorean theorem
17^2 + 12^2 = AC^2
289 + 144 = AC^2
433 = AC^2
√433 = AC
√433 is <em>about </em>20.808...
round to the tenth as stated in the directions
AC = 20.8 m
I'll say the first integer is x. The next consecutive odd number would be x+2. If the sum of the odd integers is 236, the equation would be
x + (x + 2) = 236
solve for x
2x + 2 = 236
subtract 2 from each side of the equation
2x = 234
divide both sides by 2
x = 117
117 is the first odd integer. to find the other integer (x + 2), substitute 117 for x, and you have 117 + 2, which equals 119
The two consecutive odd integers that add up to 236 are 117 and 119.
Answer:
Option (C)
Step-by-step explanation:
If AD is the altitude to BC, both the segments AD and BC will be perpendicular to each other.
By the property of perpendicular lines,
where 
is the slope of the line AD and 
is the slope of BC.
Now from the given property,
Therefore, slope of altitude BC = 
Option (C) will be the answer.
Length of PS= 3.99 units
Length of QS=2.08 units
Area of triangle PQR=14.12units²
