Answer:
S(t) = -4.9t^2 + Vot + 282.24
Step-by-step explanation:
Since the rocket is launched from the ground, So = 0 and S(t) = 0
Using s(t)=gt^2+v0t+s0 to get time t
Where g acceleration due to gravity = -4.9m/s^2. and
initial velocity = 39.2 m/a
0 = -4.9t2 + 39.2t
4.9t = 39.2
t = 8s
Substitute t in the model equation
S(t) = -49(8^2) + 3.92(8) + So
Let S(t) =0
0 = - 313.6 + 31.36 + So
So = 282.24m
The equation that can be used to model the height of the rocket after t seconds will be:
S(t) = -4.9t^2 + Vot + 282.24
Answer:
see the procedure
Step-by-step explanation:
we know that
m∠1+m∠2=180° -----> supplementary angles (form a linear pair)
we have
m∠1=27° ----> given problem
substitute the measure of m∠1 in the equation above and solve for m∠2
27°+m∠2=180°
Subtract 27° both sides
27°+m∠2-27°=180°-27° ----> by subtraction property of equality
m∠2=153°
Answer:
p > 4
Step-by-step explanation:
your welcome
Answer:
Options A-C-F
Step-by-step explanation:
we know that
<em>The circumference of a circle is equal to</em>
or 
where
D is the diameter and r is the radius
therefore
or 
The number pi is the ratio circumference - diameter or is the ratio circumference - 2 times radius
<em>The area of the circle is equal to</em>
therefore
The number pi is the ratio Area - radius squared
