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Elena L [17]
3 years ago
11

Angles helpppp plzzzzz and the plz explain with good details

Mathematics
2 answers:
slava [35]3 years ago
5 0
ABF= 28 degrees
BCD= 28  degrees since vertical angle are congruent
ABC= 180 -28 = 152 degrees
svp [43]3 years ago
5 0
X is 21 because vertical angles are congruent to each other so 4x=84. X=21 when you divide by 4 on each side.
KMH is 96 because a line is 180. 180-84=96
CBE is 118 because a line is 180. DBE is 90 so ABE also has to be 90. To find ABF it's 90-62 which is 28. CBD is also 28 because that's the vertical angle from ABF and that's congruent. so 90+28= 118. Hope this helps!
Happy Studying!
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4 0
4 years ago
A plane flying horizontally at an altitude of 1 mi and a speed of 470 mi/h passes directly over a radar station. Find the rate a
kiruha [24]

Answer:

407 mi/h

Step-by-step explanation:

Given:

Speed of plane (s) = 470 mi/h

Height of plane above radar station (h) = 1 mi

Let the distance of plane from station be 'D' at any time 't' and let 'x' be the horizontal distance traveled in time 't' by the plane.

Consider a right angled triangle representing the above scenario.

We can see that, the height 'h' remains fixed as the plane is flying horizontally.

Speed of the plane is nothing but the rate of change of horizontal distance of plane. So, s=\frac{dx}{dt}=470\ mi/h

Now, applying Pythagoras theorem to the triangle, we have:

D^2=h^2+x^2\\\\D^2=1+x^2

Differentiating with respect to time 't', we get:

2D\frac{dD}{dt}=0+2x\frac{dx}{dt}\\\\\frac{dD}{dt}=\frac{x}{D}(s)

Now, when the plane is 2 miles away from radar station, then D = 2 mi

Also, the horizontal distance traveled can be calculated using the value of 'D' in equation (1). This gives,

2^2=1+x^2\\\\x^2=4-1\\\\x=\sqrt3=1.732\ mi

Now, plug in all the given values and solve for \frac{dD}{dt}. This gives,

\frac{dD}{dt}=\frac{1.732\times 470}{2}=407.02\approx 407\ mi/h

Therefore, the distance from the plane to the station is increasing at a rate of 407 mi/h.

6 0
3 years ago
If the first number is increased by 7 and the second number is reduced by 6 times, the sum of these numbers is 29.
Marta_Voda [28]

Answer:

First number = 20

Second number = 12

Explanation:

Let the 1st number be x

Let the 2nd number be y

=====================

Condition 1

\sf \rightarrow  x + 7 + \dfrac{y}{6}  = 29

\rightarrow \sf x=-\dfrac{y}{6}+22

=====================

Condition 2

\rightarrow \sf 2y - (x - 5) = 9

\rightarrow \sf x = 2y -4

=====================

Substitute equations

\rightarrow \sf  -\dfrac{y}{6}+22 = 2y-4

\rightarrow \sf y=12

=====================

Find value of 1st number

\rightarrow \sf x = 2y - 4

\sf \rightarrow x = 2(12) - 4

\rightarrow \sf x = 20

7 0
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