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Inga [223]
3 years ago
15

A grocery sold 5kg of wheat flour at Rs30 per kg and gained 20%. If he had sold it at Rs27 per kg, what would be his gain or los

s percent.
Mathematics
1 answer:
maria [59]3 years ago
3 0

Answer:

His gain percent would have been 8%

Step-by-step explanation:

The key to answering this question is to first calculate the price at which the wheat flour was bought.

Mathematically;

% profit = (selling price-cost price)/cost price * 100%

Let the cost price be $x

Thus;

% profit = (30-x)/x * 100

20 = 100(30-x)/x

20x = 3000-100x

100x + 20x = 3000

120x = 3000

x = 3000/120

x = Rs 25

So let’s assume he sold at Rs 27

His profit would have been 27-25 = 2

His gain or loss percentage would’ve been;

2/25 * 100/1 = 200/25 = 8% (gain, since selling price is greater than the cost price)

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A cube with a volume of 729m^3 has a side length of?
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cube root the number

5 0
3 years ago
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luda_lava [24]

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8 0
3 years ago
One spring day, Kennedy noted the time of day and the temperature, in degrees
Rufina [12.5K]

Answer:

Please find attached the required graph for the temperature time relationship

Step-by-step explanation:

The parameters given are arranged in a tabular form as follows;

At

Time                                            Temperature

6 a. m.                                            56° F

7 a. m.                                             59° F

8 a. m.                                             62° F

9 a. m.                                             66° F

10 a. m.                                           70° F

11 a. m.                                            74° F

12 p. m.                                           74°F

1 p. m.                                             74°F

2 p. m.                                            74°F

3 p. m.                                            74°F

4 p. m.                                            74°F

5 p. m.                                            74°F

6 p. m.                                            74°F

7 p. m.                                            71°F

8 p. m.                                            68°F

9 p. m.                                            65°F

10 p. m.                                           62°F

11 p. m.                                            61.5°F

12 a. m.                                            61°F

With the above table as the data points, the graph can be drawn

From Excel, The Mean temperature is approximately 68.1°F

The standard deviation is 6.079 °F

3 0
3 years ago
Pls help I just need the answer​
inn [45]
That’s mainey me too
8 0
3 years ago
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